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uranmaximum [27]
2 years ago
6

1. When conducting this experiment, some procedures call for heating the substance several times and recording the mass after ea

ch heating, continuing until the mass values are constant. Explain the purpose of this process and how it might reduce errors.
Chemistry
1 answer:
zvonat [6]2 years ago
3 0

The purpose of this process is to reduce the risk of having outliers of false results.

<h3> </h3><h3>What is a good scientific experiment?</h3>

It is important to bear in mind that a good scientific experiment usually tests one independent variable at a time, and that is why it is important to keep all other potential variables constant and to use a control group.

Although, the experiment you are referring to in your question is missing the general principle when conducting an experiment is the running of multiple tests before coming up with an actual test result.

Therefore, when completing a science experiment it is important to run multiple tests like heating the substance several times until a constant mass value is obtained,  in other to ascertain the results. the reason why such process is undertaken is to reduce the risk of having outliers of false results.  

A scientific experiment involves several procedures and this depends on the type and purpose of the experiment.

for example ;

An experiment with the purpose of determining how the mass of an object reacts to heat will require the mass of the object to be recorded  after heating the object/substance several times.

Hence we can conclude that the purpose of the process is to reduce the risk of having outliers of false results.

learn more about Scientific experiment at : brainly.com/question/13184032

#SPJ1

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The reaction (CH3)3CBr + OH- (CH3)3COH + Br- in a certain solvent is first order with respect to (CH3)3CBr and zero order with r
son4ous [18]

Answer and Explanation:

The rate constant (K) is related to activation energy (Ea), frequency factor (A) and temperature (T) in Kelvin by the equation

R = molar gas constant

K = A(e^(-Ea/RT))

Taking natural log of both sides

In K = In A - (Ea/RT)

In K = (-Ea/R)(1/T) + In A

Comparing this to the equation of a straight line; y = mx + c

y = In K, slope, m = (-Ea/R), x = (1/T) and intercept, c = In A

a) From the question, m = (-Ea/R) = -1.10 × (10^4) K

(-Ea/R) = -1.10 × (10^4) = -11000

R = 8.314 J/K.mol

Ea = -11000 × 8.314 = 91454 J/mol = 91.454 KJ/mol

b) c = In A = 33.5

A = e^33.5 = (3.54 × (10^14))/s

c) K = A(e^(-Ea/RT))

A = (3.54 × (10^14))/s, Ea = 91454 J/mol, T = 25°C = 298.15 K, R = 8.314 J/K.mol

K = (3.54 × (10^14))(e^(-91454/(8.314×298.15))) = 0.0336/s

QED!

5 0
3 years ago
A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
Katen [24]

Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K  

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Gravity is responsible !
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