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2 years ago

Which of the following statements are correct based on the diagram? Select all that apply.

Mathematics

1 answer:

cluponka [151]2 years ago

7 0

Answer:

Segment U T is congruent to segment X V

Segment S T is congruent to segment W V

Angle V is congruent to angle T

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3/4 pound of Colby cheese costs $1.69. Find the unit price per pound. (3/4 pound=12)

Liula [17]

Answer:

2.25

Step-by-step explanation:

We can write a ratio to solve

1.69 x

------ = ---------------

3/4 lb 1 lb

Using cross products

1.69 * 1 = 3/4 *x

1.69 = 3/4 x

Multiply by 4/3

1.69 * 4/3 = x

x=2.25333

Rounding to the nearest cent

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3 years ago

the length of the longer leg of a right triangle is 3 ft more than three times the length of the shorter leg. the length of the

Ulleksa [173]

with the pythagorean theorem

$\begin{gathered} (4+3x)^2=x^2+(3+3x)^2 \\ 16+24x+9x^2=x^2+9+18x+9x^2 \\ 16+24x+9x^2=10x^2+18x+9 \\ 16+24x+9x^2-9=10x^2+18x+9-9 \\ 9x^2+24x+7=10x^2+18x \\ 9x^2+24x+7-18x=10x^2+18x-18x \\ 9x^2+6x+7=10x^2 \\ 9x^2+6x+7-10x^2=10x^2-10x^2 \\ -x^2+6x+7=0 \end{gathered}$

using the formula of the quadratic equation

$\begin{gathered} x_{1,\: 2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a} \\ x1=\frac{-6+\sqrt{6^2-4\left(-1\right)\cdot\:7}}{2\left(-1\right)}=-1 \\ x2=\frac{-6-\sqrt{6^2-4\left(-1\right)\cdot\:7}}{2\left(-1\right)}=7 \end{gathered}$

the length cannot be negative, therefore x=7

length of the shorter leg is: 7ft

length of the longer leg is: 3+3(7)= 24ft

length of the hypotenuse is: 4+3(7)= 25ft

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1 year ago

Factor 81a^2b^4-c^6 completely

olga nikolaevna [1]

Answer: (9ab^2+c^3)(9ab^2-c^3)

Step-by-step explanation:

81a^2b^4-c^6

(9ab^2)^2-(c^3)^2

(9ab^2+c^3)(9ab^2-c^3)

Hope this helps, HAVE A BLESSED AND WONDERFUL DAY! As well as a great Superbowl Weekend! :-)

- Cutiepatutie ☺❀❤

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3 years ago

THIRTY POINTS!!!!!!!! Write a numerical expression for the phrase ‘the quotient of 27 and the sun of -2 and -7’ then simplify it

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27 ÷ (-2 + (-7))

27 ÷ (-9)

-3

The answer is -3. Hope that helps!

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3 years ago

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2 years ago