You answer is b an oscillating wave
Answer:
t = 3.94 s
Explanation:
This can be modeled as a case of free fall motion. Because, the falcon is going down with acceleration, that is equal to acceleration due to gravity. To find the time taken by the falcon to intercept the pigeon, we will use second equation of motion for vertical direction:
where,
h = height = 76 m
vi = initial speed of falcon = 0 m/s
t = time required = ?
g = acceleration due to gravity = 9.81 m/s²
Therefore,
<u>t = 3.94 s</u>
Answer:
Explanation:
Lower the refractive index , higher the wave length
Refractive index becoming high reduces the velocity and hence wavelength as frequency remains unchanged.
So refractive index 1.4831 will correspond to wavelength of 450 nm.
For refractive index is 1.4831 , angle of incidence i , angle of refraction r .
Sin i / Sinr = 1.4831
sin65 / sinr = 1.4831
sir r = sin65 / 1.4831
= .9063 / 1.4831
= .6111
r = 37.67 degree
For refractive index is 1.4754 , angle of incidence i
Sin i / Sinr = 1.4754
sin65 / sinr = 1.4754
sir r = sin65 / 1.4754
= .9063 / 1.4754
= .61427
r = 37.9 degree
angle between two refracted ray
37.9 -37.67
= 0. 23 degree
There are 4 questions related to this problem:
1 If the half-life of the drug is 7.3 hours, what fraction of the drug remains in the patient after 24 hours?The amount of the drug is halved every 7.3-hour period, and 24 hours equals 24/7.3 of these halving periods.
So the portion of the drug left over after 24 hours is (1/2) ^ (24/7.3) = 0.10224 2 Write a general expression for the amount of the drug in the patient immediately after taking the nth dose of the drug
One method is to combine the residual amounts from each amount, when the nth dose arises; this will contain adding a finite geometric series
So the total amount of the drug immediately after the nth dose, in mg, is An = 40+ 40(0.10224) + 40(0.10224)^2 + ... + 40(0.10244)^(n-1)
An = 40[1 - (0.010224)^n]/(1 - 0.10224)
3 Write a broad expression for the quantity of the drug in the patient directly before taking the nth dose of the drug
Pn = An – 40
= 40(0.10224) + 40(0.10224)^2 + ... + 40(0.10244)^(n-1)
= 40(0.10224) [1 - (0.10224)^(n-1)]/(1 – 0.10224)
= 4.0895 [1 - (0.10224)^(n-1)]
4 What is the long-term minimum amount of drug in the patient?
= lim n-->infinity of Pn
= lim n-->infinity of 4.0895[1 - (0.10224)^(n-1)]
= 4.0895(1 - 0)
= 4.0895 mg.
Answer:
The branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.
