The answer you are looking for is A
Answer:
31.905 ft/s²
Explanation:
Given that
Mass of the pilot, m = 120 lb
Weight of the pilot, w = 119 lbf
Acceleration due to gravity, g = 32.05 ft/s²
Local acceleration of gravity of found by using the relation
Weight in lbf = Mass in lb * (local acceleration/32.174 lbft/s²)
119 = 120 * a/32. 174
119 * 32.174 = 120a
a = 3828.706 / 120
a = 31.905 ft/s²
Therefore, the local acceleration due to gravity at that elevation is 31.905 ft/s²
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers.
<h3>When was Einstein miracle year?</h3>
The miracle year for Albert Einstein was the year 1905 within which he published so many renowned papers in a short time and became very popular.
His mindset in that year was one that challenged the orthodox explanations and sought to think outside the box.
Learn more about Albert Einstein:brainly.com/question/2964376
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Answer:
E=
Explanation:
We are given that
Charge on ring= Q
Radius of ring=a
We have to find the magnitude of electric filed on the axis at distance a from the ring's center.
We know that the electric field at distance x from the center of ring of radius R is given by
Substitute x=a and R=a
Then, we get
Where K=
Hence, the magnitude of the electric filed due to charged ring on the axis of ring at distance a from the ring's center=
