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zysi [14]
2 years ago
8

You have 100 grams of different substances, the most dense substance would have which volume? A. 1L B. 0.10 L. C. 100 L D. 10 L

Physics
1 answer:
guajiro [1.7K]2 years ago
6 0
<span>Density is a value for mass, such as kg, divided by a value for volume, such as m3. Density is a physical property of a substance that represents the mass of that substance per unit volume. We do as follows:

</span><span>A. 1L
100 g /1L = 100 g/L

B. 0.10 L.
100g/0.10L = 1000 g/L ------> MOST DENSE SUBSTANCE

C. 100 L
</span>100g/100L = 1 g / L <span>

D. 10 L
</span>100g/10L = 10 g/L
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Two forces, F⃗ 1F→1F_1_vec and F⃗ 2F→2F_2_vec, act at a point,F⃗ 1F→1F_1_vec has a magnitude of 8.80 NN and is directed at an an
castortr0y [4]

Answer:

  • Fx = -9.15 N
  • Fy = 1.72 N
  • F∠γ ≈ 9.31∠-10.6°

Explanation:

You apparently want the sum of forces ...

  F = 8.80∠-56° +7.00∠52.8°

Your angle reference is a bit unconventional, so we'll compute the components of the forces as ...

  f∠α = (-f·cos(α), -f·sin(α))

This way, the 2nd quadrant angle that has a negative angle measure will have a positive y component.

  = -8.80(cos(-56°), sin(-56°)) -7.00(cos(52.8°), sin(52.8°))

  ≈ (-4.92090, 7.29553) +(-4.23219, -5.57571)

  ≈ (-9.15309, 1.71982)

The resultant component forces are ...

  • Fx = -9.15 N
  • Fy = 1.72 N

Then the magnitude and direction of the resultant are

  F∠γ = (√(9.15309² +1.71982²))∠arctan(-1.71982/9.15309)

  F∠γ ≈ 9.31∠-10.6°

4 0
3 years ago
A body oscillates with simple harmonic motion along the x axis. Its displacement varies with time according to the equation x =
frutty [35]

Answer:

θ = (7π / 3) rad

Explanation:

given,

displacement of simple harmonic motion along x-axis

equation is given as

                   x = 5 sin (π t + π/3 )

general equation of simple harmonic motion

                   x = A sin θ

           θ is the phase angle

      θ = π t + π/3

at   t = 2 s

      \theta =\pi \times 2 +\dfrac{\pi}{3}

      \theta =\dfrac{7\pi}{3}\ rad

Phase of the motion at t =2 s is θ = (7π / 3) rad

7 0
3 years ago
Two moles of an ideal monatomic gas are at a temperature of 345 K. Then, 2250 J of heat is added to the gas, and 870 J of work i
Lapatulllka [165]

Answer: The final temperature is 470K

Explanation: Using the relation;

Q= ΔU +W

Given, n = 2mol

Initial temperature T1= 345K

Heat =Q= 2250J

Workdone=W=-870J(work is done on gas)

T2 =Final temperature =?

ΔU =3/2nR(T2-T1)

ΔU=3/2 × 2 ×8.314 (T2 - 345)

ΔU=24.942(T2-345)

Therefore Q = 24.942(T2-345)+ (-870)

2250=24.942(T2-345)+ (-870)

125.09=(T2-345)

T2 =470K

Therfore the final temperature is 470K

5 0
2 years ago
Physics {deceleration}
seropon [69]
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7 0
3 years ago
Which word best describes this?<br> Particle<br> O Atom<br> O Molecule<br> O Substance
skelet666 [1.2K]
That’s an atom

I hope that helped
3 0
2 years ago
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