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zlopas [31]
3 years ago
13

A man walks 600 m [E47°N], then 500 m [N38°W], then 300 m [W29°S], and finally 400 m [S13°E]. Find his resultant displacement.

Physics
1 answer:
Archy [21]3 years ago
4 0

The horizontal component of an angular distance can be calculated by multiplying the distance with the cosine of the angle, Dx = D * cos θ

While the vertical component is calculated by multiplying the distance with the sine of the angle, Dy = D * sin θ

The resultant displacement can then be obtained using the formula for hypotenuse and summations of each component:

R^2 = (summation of Dx)^2 + (summation of Dy)^2

summation of Dx = 600 * cos47 + 500 * cos128 + 300 * cos209 + 400 * cos(-77) = -71.0372

summation of Dy = 600 * sin47 + 500 * sin128 + 300 * sin209 + 400 * sin(-77) = 297.6267

<span>                        Note: you have to draw the lines to correctly determine the angles</span>

R^2 = (-71.0372)^2 + 297.6267^2

R = 306 m

The resultant angle is:

tan θ = Dy / Dx

θ = tan^-1 (297.6267 / -71.0372)

θ = 103˚ = [N 13˚ W]

Therefore displacement is 306 m <span>[N 13˚ W].</span>

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<h3>Answer:</h3>

1.5 m/s²

<h3>Explanation:</h3>

We are given;

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The three laws of planetary motion formulated by Johannes Kepler or Kepler's laws of planetary motion:

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