B. Accelerating a bowling ball from rest to 35 m/s
Explanation:
Accelerating a bowling ball from rest to 35m/s will require more impulse compared to a baseball.
Impulse is the force acting on a body a particular period of time. It is similar to momentum.
When impulse is applied on a body, it change it state from rest and cause motion.
A body with more mass will require a higher impulse to cause it to accelerate. Bowling balls are heavier. They require more impulse to make them move.
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Answer:
<h2>1.5 ohms</h2>
Explanation:
Power is expressed as P = V²/R
R = resistance
V = supplied voltage
Given P = 600W and V = 30V
R = V²/P
R = 30²/600
R = 900/600
R = 1.5ohms
magnitude of its resistance is 1.5ohms
Answer: 339.148N
Explanation:
Data
Time (t) = 47s
U = 0m/s
V = 9.5m/s
Mass of B = 540kg
Frictional force on B = 230N
Both boats are connected so if A moves, B moves too.
Acceleration of boat A =?
Using equation of motion,
V = u + at
9.5 = 0 + a*47
a = 9.5 / 47
a = 0.2021 m/s²
The force required to accelerate boat B since it's the same force moving both boats =?
F = Mass * acceleration
F = 540 * 0.2021 = 109.14N
A frictional force of 230N exists on boat B
Total force (Tension) = frictional force + normal force = (109.15 + 230)N = 339.148N
Answer:
0.098 N
Explanation:
From the question,
Spring scale reading = W-U............... Equation 1
Where W = weight of the cube, U = upthrust.
W = mg
Where m = mass of the cube, g = acceleration due to gravity.
Given: m = 11 g = 0.011 kg, g = 9.8 m/s².
W = 0.011(9.8)
W = 0.1078 N.
From Archimedes principle,
Upthrust = weight of water displaced.
U = (Density of water×volume of metal cube)×acceleration due to gravity.
U = (D×V)g
Given: D = 1000 kg/m², V = 1 cm³ = (1/1000000) = 1×10⁻⁶ m³, g - 9.8 m/s²
U = 1000(9.8)(10⁻⁶)
U = 0.0098 N.
Substitute the value of W and U into equation 1
Reading of the spring scale = 0.1078-0.0098
Reading of the spring scale = 0.098 N
