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3 years ago

What is thermodynamics?

Physics

2 answers:

rusak2 [61]3 years ago

7 0

Answer:

The branch of physical science that deals with the relations between heat and other forms of energy (such as mechanical, electrical, or chemical energy), and, by extension, of the relationships between all forms of energy.

kvasek [131]3 years ago

7 0

Answer:

The branch of physical science that deals with the relationship between heat and energy.

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A path that allows only one route for an electric current is called a ____.

slava [35]

A path that allows only one route for an electric current is called a Series circuit. A series circuit is circuit that's arranged in a chain making it to where there's only one path to take

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3 years ago

Read 2 more answers

An 85-kg clown is fired from rest out of a 480-kg cannon. If the clown's speed is 18 meters per second after the firing, then wh

bezimeni [28]

Answer:

15.29m/s

Explanation:

Using the law of conservation of momentum

m1u1+m2u2 = (m1+m2)v

m1 is the mass of the clown = 85kg

u1 is the velocity of the clown = 0m/s (fired out from rest)

m2 is the mass of the cannon = 480kg

u2 is the velocity of the cannon = 18m/s

Let v me the recoil speed of the cannon

Substitute into the formula

85(0)+480(18) = (85+480)v

0+8640 = 565v

v = 8640/565

v = 15.29m/s

Hence the recoil speed of the cannon is 15.29m/s

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3 years ago

William Gilbert used a terella in an attempt to explain _____.

Alex787 [66]

Answer:

why compasses point towards the north and south poles of the earth.

Explanation:

hope it helps!!

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3 years ago

Calculate the average acceleration from the following data points; V1=150m/s, v2=975m/s, t1=15s, t2=55s

vladimir1956 [14]

The average acceleration is the change in velocity divided by change in time.

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4 years ago

Rafael is driving his car at 26 m/s. What is the shortest distance in which he can brake and stop if the coefficient of static f

Hitman42 [59]

Answer:

86.14 meters.

Explanation:

Step one:

Given data

velocity of car = 26 m/s

the coefficient of static friction between the tires and the road

µ = 0.4 (kinetic)

Let us take g = 9.81 m/s^2

Required

The distance x = distance in m

We know that

$N = Fg = mg\\\\F_\mu = -\mu N = \mu F_g = \mu mg\\\\KE = (1/2) mv^2$

W = F*x (Work is force times distance)

Step two:

Conservation of energy gives

KE = W

Substituting gives

$(1/2) mv^2 = F \mu x\\\\(1/2) mv^2 = \mu mgx\\\\mv^2 = 2 \mu mgx$

Solving for distance (x) gives

$x = mv^2 / 2 \mu mg$

Simplifying

$x = v^2 / 2 \mu g$

Substitute:

$x = v^2 / 2 \mu g$

$x= 26^2/2*0.4*9.81$

$x=676/7.848\\\\x=86.14$

Therefore, the minimum braking distance is 86.14 meters.

4 0

3 years ago