Answer:
The object takes approximately 1.180 seconds to complete one horizontal circle.
Explanation:
From statement we know that the object is experimenting an Uniform Circular Motion, in which acceleration (
), measured in meters per square second, is entirely centripetal and is expressed as:
(1)
Where:
- Period of rotation, measured in seconds.
- Radius of rotation, measured in meters.
If we know that
and
, then the time taken by the object to complete one revolution is:




The object takes approximately 1.180 seconds to complete one horizontal circle.
The magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
The magnitude of the force on a charged particle moving in a magnetic field is given by the formula,
F= qvB
Here q is the charge on proton = 1.6 x 10^-19 C.
v is the velocity with which the particle is moving = 6.00 x 10^6 m/s
And B is the value of the magnetic field = 1.5 T
Putting the given values in the above equation,
F = 1.6 x 10^-19 x 6 x 10^6 x 1.5 = 1.44 x 10^-12 N.
Hence, the magnitude of maximum magnetic force that could be exerted on the proton is 1.44 x 10^-12 N.
To know more about "magnetic force", refer to the link given below:
brainly.com/question/13791875?referrer=searchResults
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V = 25,364.4 cm^3 Is volumer = 2.7g/cm^3 Is density
To calculate mass you use formula:m= V*rTo avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.
the answer is :
m = 68,486,6 g
The correct answer is<span> The earth casts a shadow on the moon
The Earth casts a shadow on the moon and that's why we can't see the remaining parts. The parts that we can see are what we call the lunar phases.</span>
Initially its moving with tail wind so here the speed of wind will support the motion of the plane
so we can say



now when its moving with head wind we can say that wind is opposite to the motion of the plane



now by using above two equations we can find speed of palne as well as speed of wind

