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2 years ago

If x=2 and y =0 what is the value of x²-y(x-y)-1

Mathematics

1 answer:

dimulka [17.4K]2 years ago

5 0

Answer:

Step-by-step explanation:

x = 2

y = 0

plug in values

$2^2$ - 0(2-0)-1

4- 0(2)-1

4-0-1

4-1

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cestrela7 [59]

<h3><u>Given :- </u></h3>

$A=\left[\begin{array}{ccc}1&4\\5&6\\\end{array}\right]$
a $_{ij}$ = 6

Value of i and j

<h3><u>Solution:- </u></h3>

$\longrightarrow$ In a matrix the the the position of an element is determined by using a $_{ij}$ where i the number of row and j is number of column in which the element is.

$\leadsto$ Since 6 is in 2nd column and 2nd row <u>,</u> it's position can be written as a $_{22}$

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3 years ago

I srsly need this done now: ((5 + (1/6) divided by (2 + (5/12))

Zinaida [17]

Well in my answer i got 5.06 i rounded to the nearest hundred instead of putting all of the numbers behind the 6.

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3 years ago

Solve each equation. I don't know this

MArishka [77]

1. $(2x - 3)(x + 7) = 0$
   $2x^{2} + 14x - 3x - 21 = 0$
   $2x^{2} + 11x - 21 = 0$

   $x = \frac{-11 +/- \sqrt{11^{2} - 4(2)(-21)}}{2(2)}$

   $x = \frac{-11 +/- \sqrt{121 + 168}}{4}$

   $x = \frac{-11 +/- \sqrt{289}}{4}$

   $x = \frac{-11 +/- 17}{4}$

   $x = -2.75 +/- 4.25$
   $x = -2.75 + 4.25$    $x = -2.75 - 4.25$
   $x = 1.5$    <u></u> $x = -7$
---------------------------------------------------------------------------------------------------------- 2. $8x(2x - 5) = 0$
   $8x(2x) - 8x(5) = 0$
   $16x^{2} - 40x = 0$
   $16x^{2} - 4x + 0 = 0$

   $x = \frac{-(-40) +/- \sqrt{(-40)^{2} - 4(16)(0)}}{2(16)}$

   $x = \frac{40 +/- \sqrt{1600 - 0}}{32}$

   $x = \frac{40 +/- \sqrt{1600}}{32}$

   $x = \frac{40 +/- 40}{32}$

   $x = 1.25 +/- 1.25$
   $x = 1.25 + 1.25$       $x = 1.25 - 1.25$
   $x = 2.5$          $x = 0$
----------------------------------------------------------------------------------------------------------
3. $x^{2} + 3x - 10 = 0$

   $x = \frac{-3 +/- \sqrt{3^{2} - 4(1)(-10)}}{2(1)}$

   $x = \frac{-3 +/- \sqrt{9 + 40}}{2}$

   $x = \frac{-3 +/- \sqrt{49}}{2}$

   $x = \frac{-3 +/- {7}}{2}$

   $x = -1.5 +/- 3.5$
   $x = -1.5 + 3.5$    $x = -1.5 - 3.5$
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4. $x^{2} = 13x - 36$
    $x^{2} - 13x + 36 = 13x - 13x - 36 + 36$
    $x^{2} - 13x + 36 = 0$

    $x = \frac{-(-13) +/- \sqrt{(-13)^{2} - 4(1)(36)}}{2(1)}$


    $x = \frac{13 +/- \sqrt{169 - 144}}{2}$

    $x = \frac{13 +/- \sqrt{25}}{2}$

    $x = \frac{13 +/- 5}{2}$

    $x = 6.5 +/- 2.5$
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----------------------------------------------------------------------------------------------------------
5. $3x^{2} - 7x + 2 = 0$

   $x = \frac{-(-7) +/- \sqrt{(-7)^{2} - 4(1)(2)}}{2(3)}$

   $x = \frac{7 +/- \sqrt{49 - 8}}{6}$

   $x = \frac{7 +/- \sqrt{41}}{6}$

   $x = \frac{7 +/- 6.403124237432849}{6}$

   $x = 1.167+/- 1.06718737290547$
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   $x = \frac{14 +/- \sqrt{36}}{10}$ .

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4 years ago

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lesya [120]

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3 years ago

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3.10 is correct hope this helps!!

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3 years ago