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expeople1 [14]
3 years ago
14

HELP PLEASEEEE >.< Its 8 pm and I'm tired :c

Mathematics
1 answer:
dedylja [7]3 years ago
8 0

Answer:

is I don't know really a option L.MAOO

anyway option 3,4, and 5 ( maybe 6 but not sure) are correct

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Which of the following is the equation of the line that has a slope of negative three and passes through the point begin ordered
Musya8 [376]
It’s negative 4 your welcome
8 0
1 year ago
21/33 Marks
Marrrta [24]

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Step-by-step explanation:

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8 0
3 years ago
Write a ratio for this number
Vladimir79 [104]

Answer:

o/3 or 1/1

Step-by-step explanation:

8 0
3 years ago
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Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
Solve y = x2 + 2 for x.
stiks02 [169]

Answer:

x = y - 2 / 2

Step-by-step explanation:

y = 2x + 2

2x + 2 = y

2x = y - 2

x = y - 2 / 2

6 0
2 years ago
Read 2 more answers
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