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Art [367]
2 years ago
11

the temperature in mayfield at 6pm was 5 degrees fahrenheit. by 11pm the temperature dropped 9 degrees. enter the temp in degree

s fahrenheit at 11pm
Mathematics
2 answers:
lys-0071 [83]2 years ago
4 0

Answer: the answer is - 4

Step-by-step explanation:

Ok so it decrased by 9 degrees so what you do is 5 - 9 which would be negative four.    -4

Elan Coil [88]2 years ago
3 0

Answer:

-4°F

Step-by-step explanation:

Starting temp minus amount dropped gives ending temp.

5 - 9 = -4

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lara [203]

Answer:

The function given in the question isg(x) = 4x - 5When x = 2, theng(2) = (4 * 2) - 5 = 8 -5 ...

Step-by-step explanation:.

5 0
2 years ago
Ind the roots of 3(x – 2)2 = 12.
blagie [28]

Answer:

x=4

Step-by-step explanation:

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6 0
3 years ago
Wilma is twice as old as Jamal, and Jamal is 3 years older than Tim. The sum of all their ages is 17. Let j be Jamal's age. Writ
m_a_m_a [10]
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7 0
3 years ago
Solve 5(x/2+3)=35 what is the answer
evablogger [386]

Answer:

x=8

Step-by-step explanation:

5(x/2+3)=35

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x/2+3=7

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8 0
3 years ago
Read 2 more answers
How do you do this question?
Gemiola [76]

Answer:

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

Step-by-step explanation:

∫ 15 sin(√(at)) dt

Use substitution:

If x = √(at), then:

dx = ½ (at)^-½ (a dt)

dx = a / (2√(at)) dt

dx = a/(2x) dt

dt = (2/a) x dx

Plugging in:

∫ 15 sin x (2/a) x dx

30/a ∫ x sin x dx

Integrate by parts:

If u = x, then du = dx.

If dv = sin x dx, then v = -cos x.

∫ u dv = uv − ∫ v du

= 30/a (-x cos x − ∫ -cos x dx)

= 30/a (-x cos x + ∫ cos x dx)

= 30/a (-x cos x + sin x + C)

Substitute back:

30/a (-√(at) cos(√(at)) + sin(√(at)) + C)

-30√(t/a) cos(√(at)) + 30/a sin(√(at)) + C

5 0
3 years ago
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