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kondor19780726 [428]
2 years ago
14

Although time is one of those concepts which we are all familiar with, it is difficult to define. We can say it is what is measu

red by a clock or that it is nature's way of seeing that everything does not happen at once.
What are your Thoughts on this?

do you think time is real?
Physics
1 answer:
Tema [17]2 years ago
3 0

Explanation:

time is nature's expression of change.

every change takes time.

it takes time to e.g. move from A to B.

at one point of time the universe is in one state, then some change happens, and the universe is in another state, and we have another point of time.

without time there is no change, without change there is no time.

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Why does it take the water in a swimming pool some time to heat up during a hot day?
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Because the top layer of a pool will be warmer than the bottom layer, that why filtration is important to cycle the water evenly.
5 0
4 years ago
All of the following are regulated by the medulla except
Fantom [35]

Answer:

D. flight or flight response.

Explanation:

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6 0
4 years ago
Push-and-pull factors contribute to _____.<br> economics<br> politics<br> migration<br> education
kaheart [24]

c) migration

Push factors are the reasons why people leave an area. Pull factors are the reasons why people move to a particular area.

7 0
3 years ago
A flywheel is a solid disk that rotates about an axis that is perpendicular to the disk at its center. Rotating flywheels provid
Sergeeva-Olga [200]

Answer:

8.37*10^5 rpm

Explanation:

Given that rotational kinetic energy = 4.66*10^9J

Mass of the fly wheel (m) = 19.7 kg

Radius of the fly wheel (r) = 0.351 m

Moment of inertia (I) = \frac{1}{2} mr ^2

Rotational K.E is illustrated as (K.E)_{rt} = \frac{1}{2} I \omega^2

\omega = \sqrt{\frac{2(K.E)_{rt}}{I} }

\omega = \sqrt{\frac{2(KE)_{rt}}{1/2 mr^2} }

\omega = \sqrt{\frac{4(K.E)_{rt}}{mr^2} }

\omega = \sqrt{\frac{4*4.66*10^9J}{19.7kg*(0.351)^2} }

\omega = 87636.04

\omega = 8.76*10^4 rad/s

Since 1 rpm = \frac{2 \pi}{60}  rad/s

\omega = 8.76*10^4(\frac{60}{2 \pi})

\omega = 836518.38

\omega = 8.37 *10^5 rpm

3 0
3 years ago
Suppose that the loudspeaker in the problem had a mass of 500 kg and the ropes hung 20∘ from the vertical. Into which of the fol
nexus9112 [7]

The following intervals would you expect T(tension) to fall : <u>2000 to 4000 N </u>

<h3>Further explanation</h3>

The force acting on a system with static equilibrium is 0

\large{\boxed{\bold{\sum F=0}}

(forces acting as translational motion only, not including rotational forces)

\displaystyle \sum F_x = 0\\\\ \sum F_y = 0

We complete the questions:

A 20-kg loudspeaker is suspended 2.0 m below the ceiling by two ropes that are each 30? from vertical.

Find the value of T, the magnitude of the tension in either of the ropes.

Express your answer in newtons.

Suppose that the loudspeaker in the problem has a mass of 500 kg and the ropes hung 20? from the vertical. Into which of the following intervals would you expect T to fall? You don't have to calculate Texactly to answer this question; just make an estimate.

500 to 1000 N

1000 to 2000 N

2000 to 4000 N

4000 to 8000 N

8000 to 16,000 N

In a 500-kg loudspeaker system and two ropes that are each 20° from vertical, we see the forces acting on the y axis (vertical)

\displaystyle \sum F_y = 0\\\\T1_y+T2_y-w=0\\\\T1~cos~20^o+T2~cos~20^o=m\times g

we assume g = 10 m/s², then :

\displaystyle 2T~cos~20=500\times 10\\\\T~cos~20=2500\\\\\boxed{\bold{T=26592 N}}}

So the value of T is between 2000 and 4000 N

<h3>Learn more</h3>

Newton's Law

brainly.com/question/13725525

Keywords : the loudspeaker, ropes, Tension, mass, intervals

#LearnWithBrainly

4 0
4 years ago
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