3 years ago

List 10 examples of Science (things that are created by nature or in their natural state)

Physics

2 answers:

Ronch [10]3 years ago

7 0

Answer:

Stone

Air

Water

All Elements Of the Periodic Table

Plants

The Sun

Grime

Sand

Climate

Food That Grows On Plants

Explanation:

nekit [7.7K]3 years ago

6 0

Atoms
Cells
Trees
Flowers
Rocks
Animals
Humans
Chemicals
Gas
Water

You might be interested in

70 pointss yall !!! helpp

Ilya [14]

A: the type of plant

B: how tall the plant is

5 0

4 years ago

Read 2 more answers

A truck accelerating at 0.0083 meters/secondÆ covers a distance of 5.8 × 10Ê meters. If the truck's mass is 7,000 kilograms, wha

tigry1 [53]

work done = force * distance moved (in direction of the force)

force= mass* acceleration

force=58.1N

58.1*(5.8*10^4)
=3,369,800 J

3 0

3 years ago

Read 2 more answers

Which of these is an example of a mechanical wave? A. the light of the Sun B. a car stuck in traffic C. the shaking from an eart

sesenic [268]

A Explanation: I took this test before

5 0

3 years ago

The barometric pressure in breckenridge, colorado (elevation 9600 feet) is 580 mm hg. how many atmospheres is this?

Maksim231197 [3]

1 atmospheric pressure = 760.0 mm Hg

Thus 580 mm Hg = (580 mm Hg/(760 mm Hg/atm))

= 0.763 atm

7 0

3 years ago

Assume that the loop is initially positioned at θ=30∘θ=30∘ and the current flowing into the loop is 0.500 AA . If the magnitude

labwork [276]

Answer: $\tau=1.03\times 10^{-4}\ N-m$

Torque,

Explanation:

Given that,

The loop is positioned at an angle of 30 degrees.

Current in the loop, I = 0.5 A

The magnitude of the magnetic field is 0.300 T, B = 0.3 T

We need to find the net torque about the vertical axis of the current loop due to the interaction of the current with the magnetic field. We know that the torque is given by :

$\tau=NIAB\ \sin\theta$

Let us assume that, $A=0.0008\ m^2$

$\theta$ is the angle between normal and the magnetic field, $\theta=90^{\circ}-30^{\circ}=60^{\circ}$

Torque is given by :

$\tau=1\times 0.5\ A\times 0.0008\ m^2\times 0.3\ T\ \sin(60)\\\\\tau=1.03\times 10^{-4}\ N-m$

So, the net torque about the vertical axis is $1.03\times 10^{-4}\ N-m$ . Hence, this is the required solution.

4 0

3 years ago