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creativ13 [48]
3 years ago
8

Make a rule: how would you find the resistance of a parallel circuit with n identical resistors?

Physics
1 answer:
Kobotan [32]3 years ago
6 0
When n resistors are connected in parallel, it means they are connected to the same potential difference V:
V=V_1 =V_2 =...=V_n (2)
It also means that the total current in the circuit is given by the sum of the currents flowing through each branch (each resistor) of the circuit:
I=I_1+I_2 +...+I_n (1)

By using Ohm's law:
I= \frac{V}{R}
we can rewrite (1) as
\frac{V}{R_{eq}} =  \frac{V_1}{R_1}+ \frac{V_2}{R_2}+...+ \frac{V_n}{R_n}
However, we said that the potential difference across each resistor is equal (eq.(2)), so we can rewrite the last formula as
\frac{V}{R_{eq}} = \frac{V}{R_1}+ \frac{V}{R_2}+...+ \frac{V}{R_n}
From which we find an expression for the equivalent resistance of n resistors in parallel:
\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+....+ \frac{1}{R_n}
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5 0
3 years ago
Classify the following situations as involving balanced or unbalanced forces.
Murrr4er [49]

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Explanation:

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5 0
3 years ago
Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t
Readme [11.4K]

Answer: 3.66(10)^{33}kg

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity \omega of the planet P1 with a period T=750years=2.36(10)^{10}s:

\omega=\frac{2\pi}{T}=\frac{V_{1}}{R} (1)

Where:

V_{1}=40.2km/s=40200m/s is the velocity of planet P1

R is the radius of the orbit of planet P1

Finding R:

R=\frac{V_{1}}{2\pi}T (2)

R=\frac{40200m/s}{2\pi}2.36(10)^{10}s (3)

R=1.5132(10)^{14}m (4)

On the other hand, we know the gravitational force F between the star S with mass M and the planet P1 with mass m is:

F=G\frac{Mm}{R^{2}} (5)

Where G is the Gravitational Constant and its value is 6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}

In addition, the centripetal force F_{c} exerted on the planet is:

F_{c}=\frac{m{V_{1}}^{2}}{R^{2}} (6)

Assuming this system is in equilibrium:

F=F_{c} (7)

Substituting (5) and (6) in (7):

G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}} (8)

Finding M:

M=\frac{V^{2}R}{G} (9)

M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}} (10)

Finally:

M=3.66(10)^{33}kg (11) This is the mass of the star S

4 0
4 years ago
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Alchen [17]

Answer:

A.

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2.the order was to heat the bowl, let it boil, then place the butter in.

3.The heat got from the water to the butter by placing it on the spoon then physically moving it into the hot bowl.

4.objects that do not conduct heat are called insulators.

B.

1. When the ice cube got placed into the water it immediately melted.

2.the water from the ice cube to the warm water as soon as it got laced it immediately melted.

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TABLE A: when I placed the butter in it melted a little bit slower than the ice cube but it still melted very fast.

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TABLE C: room temp water:75 degrees

cold water:50

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TABLE D: when I blew out the candle the flame went but the smoke started to rise up.

TABLE E: the small beaker heated up quicker and I observed that the less amount of mass the faster it will heat up.

TABLE F: the black piece of paper heated up quicker and I believe its because the darker color the more mount of heat is attracted.

Explanation: I HOPE THIS HELPED! BRAINLESS?

8 0
3 years ago
Determine the value of the resistor r so that a current of 0.5a flows through the load.
iren2701 [21]
What is the value of the voltage? There must be one somewhere.

This might be too simple minded, but I'll give it a voltage of 10 Volts.

R = voltage / Current
R = 10 / 0.5
R = 20 volts. 

Perhaps you could post a diagram if this is a Kirchhoff Law Question.
8 0
3 years ago
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