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irina [24]
4 years ago
14

A bowling ball encounters a 0.760 m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictiona

l losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 4.50 m/s at the bottom of the rise. Find the translational speed at the top.
Physics
1 answer:
xxMikexx [17]4 years ago
5 0

Answer:

v = 2.31 m/s

Explanation:

Kinetic energy will be converted partially into potential energy and rest will remain in the form of kinetic energy .

Initial kinetic energy = 1/2 mu²

u is initial velocity at the bottom .

Potential energy at the top

= mgh

Kinetic energy at the top

= 1/2 m v²

According to conservation of energy

1/2 mu² = mgh + 1/2 m v²

1/2 u² = gh + 1/2  v²

.5 x 4.5² = 9.8 x .76 + .5 v²

10.125 = 7.448 + .5 x v²

v = 2.31 m/s

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