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irina [24]
4 years ago
14

A bowling ball encounters a 0.760 m vertical rise on the way back to the ball rack, as the drawing illustrates. Ignore frictiona

l losses and assume that the mass of the ball is distributed uniformly. The translational speed of the ball is 4.50 m/s at the bottom of the rise. Find the translational speed at the top.
Physics
1 answer:
xxMikexx [17]4 years ago
5 0

Answer:

v = 2.31 m/s

Explanation:

Kinetic energy will be converted partially into potential energy and rest will remain in the form of kinetic energy .

Initial kinetic energy = 1/2 mu²

u is initial velocity at the bottom .

Potential energy at the top

= mgh

Kinetic energy at the top

= 1/2 m v²

According to conservation of energy

1/2 mu² = mgh + 1/2 m v²

1/2 u² = gh + 1/2  v²

.5 x 4.5² = 9.8 x .76 + .5 v²

10.125 = 7.448 + .5 x v²

v = 2.31 m/s

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The principle of conservation of momentum is most similar to which of newton's laws of motion?
Effectus [21]
Newton’s Thrid Law, which states that for every reaction there is an opposite reaction.
6 0
3 years ago
A parachutist of mass 20.1 kg jumps out of an airplane at a height of 662 m and lands on the ground with a speed of 7.12 m/s. Th
Klio2033 [76]

Answer:

1.30\cdot 10^5 J

Explanation:

The energy lost due to air friction is equal to the mechanical energy lost by the parachutist during the fall.

The initial mechanical energy of the parachutist (at the top) is equal to his gravitational potential energy:

E_i=mgh

where

m = 20.1 kg is his mass

g=9.8 m/s^2 is the acceleration due to gravity

h = 662 m is the initial heigth

The final mechanical energy (at the bottom) is equal to his kinetic energy:

E_f=\frac{1}{2}mv^2

where

v = 7.12 m/s is the final speed of the parachutist

Therefore, the energy lost due to air friction is:

\Delta E=E_i-E_f=mgh-\frac{1}{2}mv^2=(20.1)(9.8)(662)-\frac{1}{2}(20.1)(7.12)^2=1.30\cdot 10^5 J

4 0
4 years ago
An electron having 500ev energy enters at right angle to a uniform magnetic field of 10^-4 Tesla. If its specific charge is 1.75
gtnhenbr [62]

Answer:

The correct answer might be r = 2.8^{27} meters.

Explanation:

<u>The Answer Given might not be correct, I just did what my brain said.</u>

As the angle is perpendicular so Θ=90.

Putting this in the equation to calculate the magnetic force as:

F = evBsinΘ

F= evBsin90                   *sin90 = 1 so,

F= evB.

Now when the electron will start to move in  a circle, The necessary force that makes the electron rotate in a circle is given by Centripetal force.

So,

    Magneteic Force = Centripetal Force

    evB = \frac{mv^{2} }{r}

    r = \frac{mv}{Be} ......(1)

Now the problem is, We don't know " v " so we need to calculate velocity first,

Calculation of Velocity:

                                   In order to calculate the velocity of electron, We should know the potiential difference with which the electrons are accelerated which in our case is 500ev. If "V" is the potiential difference, the energy gained by electrons during accelreation will be Ve. This appear as kinectic enrgy of electrons as,

         

                        K.E = Ve

                        \frac{1}{2}mv^{2} = Ve

                        v =  \sqrt{\frac{2ve}{m} }................(2)

Putting value of velocity in equation 2 from 1:

r = \frac{mv}{Be}  \sqrt{\frac{2ve}{m} }

r = \sqrt{\frac{2mev}{Be}}

r = \sqrt{\frac{(2)(9.1^{-31})(500) (1.6^{-19} )  }{ (1.75^{11} ) (10^{-4} ) } }

r = 2.8^{27} meters.

                               

8 0
3 years ago
A popular car stereo has four speakers, each rated at 60 W. In answering the following questions, assume that the speakers produ
Fantom [35]

Answer:

Explanation:

Intensity of sound = sound energy emitted by source / 4 π d² , where d is distance of the source .

A )

Intensity of sound at 1 m distance = 60 /4 π d²

d = 1 m

Intensity of sound at 1 m distance = 60 /(4 π 1²)

= 4.78 W m⁻² s⁻¹

B )

Intensity of sound at 1.5 m distance = 60 /4 π d²

d = 1.5  m

Intensity of sound at 1 m distance = 60 /(4 π 1.5²)

= 2.12 W m⁻² s⁻¹

C )

Intensity of sound due to 4 speakers at 1.5 m distance = 4 x 60 /4 π d²

d = 1.5  m

= 4 x 60 /(4 π 1.5²)

= 8.48 W m⁻² s⁻¹

D )

Intensity of sound due to .06 W speaker must be 10⁻¹² W s ⁻² . Let the distance be d .

.06 /4 π d² = 10⁻¹²

d² = .06 /4 π 10⁻¹²

d = 6.9 x 10⁴ m .

7 0
3 years ago
The National Grid supplied a house with 18,000,000 J of energy in 1 hour. What was the average current supplied to the house dur
alex41 [277]

I got 0.0126, but it feels wrong.

7 0
4 years ago
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