Wouldnt -128m^6 be the answer if there is no value for m?
Assume you mean the transformation from x^2 to (x-10)^2 + 8
Then, you first shift x^2 10 units right, you will get (x-10)^2
And, shift (x-10)^2 8 units upward, you will get (x-10)^2 + 8
The denominator of 4 and 6 is ... (LCM) = 24
4,8,12,16,20,24
6,12,18,24
Answer:
x = pp12 or 12 pp
Step-by-step explanation:
Just to note that pp means p square
