When the three integers 400, 366, and 213 are divided by a positive integer d > 1, the remainders are the same. What is the l
1 answer:
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Answer:
The simplest form of is
Step-by-step explanation:
To add two algebraic fractions do these steps
- Factorize each denominator
- Simplify each fraction to its lowest term
- Find the LCM of the two denominators
- Divide LCM by each denominator and multiply the numerators by its corresponding quotients
- Add the two fraction and simplify the last answer
To simplify
Factorize each denominator
∵ The denominator of the first fraction is x² + 5x + 6
∵ x² = (x)(x)
∵ 6 = (2)(3)
∵ (2)(x) + (3)(x) = 5x ⇒ middle term
∴ x² + 5x + 6 = (x + 2)(x + 3)
∵ The denominator of the second fraction is x² + 3x + 2
∵ x² = (x)(x)
∵ 2 = (2)(1)
∵ (2)(x) + (1)(x) = 3x ⇒ middle term
∴ x² + 3x + 2 = (x + 2)(x + 1)
Find the LCM of the two denominators
∵ The denominators are (x + 2)(x + 3) and (x + 2)(x + 1)
- LCM is all the <u><em>different factors</em></u> multiplied together
∴ LCM of them is (x + 1)(x + 2)(x + 3)
- Divide LCM by each denominator
∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 3) = (x + 1)
- Multiply the numerator of the first fraction by (x + 1)
∵ (x + 1)(x + 2)(x + 3) ÷ (x + 2)(x + 1) = (x + 3)
- Multiply the numerator of the second fraction by (x + 3)
∴ =
- Add the numerators and write the answer as a single fraction
∴ =
- Factorize the numerator by taking 2 as a common factor
∵ 2x + 4 = 2(x + 2)
∴ =
- Simplify the fraction by dividing up and down by (x + 2)
∴ =
The simplest form of is
