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soldi70 [24.7K]
3 years ago
9

Write two expressions where the solution is 19

Mathematics
2 answers:
Schach [20]3 years ago
8 0

You could do 10+9=19 and 12+7=19
trasher [3.6K]3 years ago
8 0
You can also do 13+6 or 23-4
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What is the tru solution to the logarithmic equation below? Log4[log4(2x)]=1
zaharov [31]

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Take both sides as powers of 4:

4^{\log_4(\log_42x)}=4^1\implies\log_42x=4

Do it again:

4^{\log_42x}=4^4\implies2x=(2^2)^4=2^8\implies x=2^7=128

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Step-by-step explanation:

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3 years ago
5cosx -2sin(x/2) +7=0<br>Help me to find x step by step<br>pls​
miskamm [114]

Answer:

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Step-by-step explanation:

First, you need to know

1. Double-angle formula:

cos(2x) = cos^{2}x - sin^{2}x

2. Pythagorean identity:

cos^{2}x + sin^{2}x = 1

Back to your problem, replacing the variable by the above:

5cosx-sin\frac{x}{2}+7 = 0

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Given y = \frac{x}{2}

5(1-2sin^{2}y) - 2siny + 7 = 0

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Answer:

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-1/3 - 1 2/3 =

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8 0
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Read 2 more answers
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