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Ymorist [56]
2 years ago
7

Ben is climbing a tree with a lot of branches. His height off the ground at time $t$ is $2t^2-5t+29$ feet. To the nearest foot,

what will his minimum height be?
Mathematics
2 answers:
Ilia_Sergeevich [38]2 years ago
4 0

Ben minimum height above the ground when climbing the tree would be 25.875 feet

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Given that:

h(t) = 2t² - 5t + 29

The minimum height is at h'(t) = 0, hence:

h'(t) = 4t - 5

4t - 5 = 0

t = 5/4

h(5/4) = 2(5/4)² - 5(5/4) + 29 = 25.875 feet

Ben minimum height above the ground when climbing the tree would be 25.875 feet

Find out more on equation at: brainly.com/question/2972832

Romashka [77]2 years ago
4 0

Using the vertex of the quadratic equation, it is found that his minimum height will be of 25.875 feet.

<h3>What is the vertex of a quadratic equation?</h3>

A quadratic equation is modeled by:

y = ax^2 + bx + c

The vertex is given by:

(x_v, y_v)

In which:

x_v = -\frac{b}{2a}

y_v = -\frac{b^2 - 4ac}{4a}

Considering the coefficient a, we have that:

  • If a < 0, the vertex is a maximum point.
  • If a > 0, the vertex is a minimum point.

In this problem, the equation is:

h(t) = 2t² - 5t + 29.

Hence the coefficients are a = 2 > 0, b = -5, c = 29, and the minimum height in feet is given by:

y_v = -\frac{(-5)^2 - 4(2)(29)}{4(2)} = 25.875

More can be learned about the vertex of a quadratic equation at brainly.com/question/24737967

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