3 years ago

Help again?????????????

Mathematics

1 answer:

vesna_86 [32]3 years ago

5 0

Answer:

The answer is D

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Solve by using square root: <br> 4(x-1)^2+2=10

Scilla [17]

$4(x-1)^2+2=10\\\\4(x^2-2x+1)+2-10=0\\\\4 x^2-8x+4+2-10=0\\\\4 x^2-8x-4=0\ \ / :4\\\\x^2-2x-1=0\\\\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{2-\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2-\sqrt{ 8}}{2 }=\frac{2- \sqrt{ 4*2}}{2 }=\\\\=\frac{2-\sqrt{ 8}}{2 }=\frac{2(1- \sqrt{ 2})}{2 }=1- \sqrt{ 2}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{2+\sqrt{ (-2)^2-4*1*(-1)}}{2 }=\frac{2(1+ \sqrt{ 2})}{2 }=1+ \sqrt{ 2}$

$Answer:\ x=1- \sqrt{2}\ \ or\ \ x= 1+ \sqrt{ 2}$

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3 years ago

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Simone and Spencer Competed in a race. after 45 minutes, simone had finished 2/5 of the race. And Spencer had finished 6 /8 of t

masya89 [10]

Spencer because 6/8 is more than 2/5.

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3 years ago

Simplify. Assume that no denominator is equal to zero.

maria [59]

Answer:

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