All categories

2 years ago

What is the slope-intercept equation of the line below?

Mathematics

1 answer:

Sedbober [7]2 years ago

7 0

Answer:

$Consider points (3,5) and (2,-5) from the graph \\ slope = \frac{( - 5 - 5)}{(2 - 3)} \\ m = 10 \\ in \: relation \: of \: (3,5) \: with \: y = mx + c \\ 5 = (10)(3) + c \\ 5 = 30 + c \\ c = - 25 \\ y = 10x - 25 \\ \frac{y}{5} = 2x - 5$

You might be interested in

What is 63×.04 as a decimal

liraira [26]

63 x .04 = 2.52

That is your answer to the question! Hope I helped :)

3 0

2 years ago

Please help me answer this question and show work

maria [59]

Answer:

c=45 and A=145

M=15 and L=115

Step-by-step explanation:

6 0

2 years ago

Estimate the slope of the tangent line of the function y(t)=\sqrt{(3t+1} at the point t=2.

Korvikt [17]

Answer: 0.567

Step-by-step explanation:

$y(t)=\sqrt{3t+1} \\\\y'(t)=\dfrac{3}{2\sqrt{3t+1} } \\\\y'(2)=\dfrac{3}{2\sqrt{3*2+1} } =\dfrac{3\sqrt{7} }{14} =0,56694670951384084082177480435127\approx{0.567}$

7 0

3 years ago

(3.2 x 10^14) (5.1 x 10^2) in scientific notation

tresset_1 [31]

Those expressions are already in scientific notation.

6 0

3 years ago

For the graphed exponential equation, calculate the average rate of change from x = −3 to x = 0.

iragen [17]

Answer:

$-\frac{7}{3}$

Step-by-step explanation:

To solve this, we are using the average rate of change formula:

$m=\frac{f(b)-f(a)}{b-a}$

where

$m$ is the average rate of change

$a$ is the first point

$b$ is the second point

$f(a)$ is the function evaluated at the first point

$f(b)$ is the function evaluated at the second point

We want to know the average rate of change of the function $f(x)=0.5^x-6$ form x = -3 to x = 0, so our first point is -3 and our second point is 0. In other words, $a=-3$ and $b=0$ .