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Naddik [55]
3 years ago
15

Helppppppppppppp!!!!!!

Mathematics
2 answers:
n200080 [17]3 years ago
8 0

Question 1:

For this case, let the variable "x" be the number of girls in the classroom. Let the variable "y" be the number of boys in the classroom.

We propose the equations:

x + y = 22\\x = y + 12

We substitute the second equation in the first:

y + 12 + y = 22\\2y = 22-12\\2y = 10\\y = 5

So, in the classroom there are 5 boys.

x = 5 + 12\\x = 17

So, there are 17 girls.

Answer:

5 guys

17 girls

Question 2:

For this case we have to:

Let x be the variable that represents the amount of money Jamie has.

Let y the variable that represents the amount of money that Kristen has

We have to:

x = 2y\\x + y = 36

We substitute the first equation in the second:

2y + y = 36\\3y = 36\\y = \frac {36} {3}\\y = 12

Looking for the value of x:

x = 2 (12)\\x = 24

Answer:

So, Jaime you have $ 24 and Kristen you have $ 12.

Question 3:

For this case we have to:

Let "x" be the variable that represents the number of dogs in the Pet Stop.

Let "y" be the variable that represents the number of cats in the Pet Stop.

We have to:

x + y = 15\\4x = y

We substitute the second equation in the first:

x + 4x = 15\\5x = 15\\x = \frac {15} {5}\\x = 3

We look for the value of y:

y = 4x\\y = 4 (3)\\y = 12

So, there are 12 cats and 3 dogs.

Answer:

12 cats

3 dogs

Anon25 [30]3 years ago
6 0

Answer:

<h2>There are 17 girls and 5 boys.</h2>

Step-by-step explanation:

Let b and g represent the number of boys and the number of girls respectively.

Then b + g = 22 (students), and g = b + 12.

Substituting b + 12 for g in b + g = 22 yields:

b + (b + 12) = 22

or:

2b + 12 = 22, or 2b = 10, so that b = 5.

Then g = b + 12 = 5 + 12 = 17.

There are 17 girls and 5 boys.

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Pure copper was mixed with a 10% copper alloy to produce an alloy thát was 25% copper. How much of the pure copper and how much
lora16 [44]

Answer:

6kg pure copper and 30 kg 10% copper was mixed to give 36kg of 25% alloy

Step-by-step explanation:

Here, we want to produce 36 kg of 25% alloy

Let the Pure copper be x kg while 10% alloy be y kg

Pure copper is simply 100% copper

Thus;

x + y = 36 •••••(i)

Then;

100% of x + 10% of y = 25% of 36

= x + 0.1y = 9 •••••• ii)

From i x = 36-y

from ii, x = 9-0.1y

Equate both x

36-y = 9-0.1y

36-9 = 0.1y + y

0.9y = 27

y = 27/0.9

y = 30

x = 36-y

x = 36-30

x = 6 kg

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2 years ago
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Answer:

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Step-by-step explanation:

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IRINA_888 [86]

Answer:

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Step-by-step explanation:

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