We have the following equation:
3x2 + 7x + 4 = 0
Using the resolver we have:
x = (- b +/- root (b2 - 4ac)) / 2a
Substituting values we have:
x = (- (7) +/- root ((7) 2 - 4 (3) (4))) / 2 (3)
Rewriting:
x = (- 7 +/- root (49 - 48)) / 6
x = (- 7 +/- root (1)) / 6
x = (- 7 +/- 1) / 6
The results are:
x = (- 7 + 1) / 6 = -6/6 = -1
x = (- 7 - 1) / 6 = -8 / 6 = -4/3
Answer:
x = -1
x = -4/3
option C and D
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3x^4 becomes 3(3x)^4=3*3^4*x^4
y^2 becomes (3y)^2=3^2y²
the new z=3² the old z, so b is correct.
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Answer:
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