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NemiM [27]
3 years ago
12

Someone help me with 5.84 divide 4

Mathematics
2 answers:
asambeis [7]3 years ago
4 0

Answer:

1.46

Step-by-step explanation:

Tcecarenko [31]3 years ago
3 0
Answer is 1.46, have a great day!
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PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER!!
ludmilkaskok [199]

Answer:

Option D, 192 m³

Step-by-step explanation:

Volume = base area × height

= (6×8/2)×8

= 192 m³

5 0
3 years ago
The base diameter and the height of a cone are both<br> equal to x units.
Vera_Pavlovna [14]

Answer:

π x³ /12 is the volume of the cone if  A cone has a height of x and a diameter of x

Step-by-step explanation:

The base diameter and the height of a cone are both equal to x units

Diameter of cone = x  units

Radius = Diameter /2

=> Radius of cone = x/2 units

Height of cone =x units

Volume of cone = (1/3) π r²h

r = radius h = height

=> Volume of cone =  (1/3)π (x/2)² * x

= (1/3) π (x²/4) * x

= (1/12)  π x³

= π x³ /12 cubic units

6 0
2 years ago
Ted and Robin each gave a basket of green apples to their friend Lily. Ted’s basket contains 5 apples, each weighing 7 1/4 ounce
AnnyKZ [126]
Robins basket is heavier.
Teds basket: 5x7.25=36.25
Robins basket: 6x6.25=37.5
37.5-36.25= 1.25
It is heavier by 1.25 ounces or 1 and 1/4 ounces
8 0
3 years ago
What is the perimeter of this quadrilateral?<br> (5,5)<br> (2, 4)<br> (4, 1)<br> (6, 1)
lbvjy [14]

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{5}~,~\stackrel{y_1}{5})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{[ 2- 5]^2 + [ 4- 5]^2} \\\\\\ AB=\sqrt{(-3)^2+(-1)^2}\implies \boxed{AB=\sqrt{10}} \\\\[-0.35em] ~\dotfill\\\\ B(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{4}~,~\stackrel{y_2}{1}) ~\hfill BC=\sqrt{[ 4- 2]^2 + [ 1- 4]^2}

BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{4}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{6}~,~\stackrel{y_2}{1}) ~\hfill CD=\sqrt{[ 6- 4]^2 + [ 1- 1]^2} \\\\\\ CD=\sqrt{2^2+0^2}\implies \boxed{CD=2} \\\\[-0.35em] ~\dotfill\\\\ D(\stackrel{x_1}{6}~,~\stackrel{y_1}{1})\qquad A(\stackrel{x_2}{5}~,~\stackrel{y_2}{5}) ~\hfill DA=\sqrt{[ 5- 6]^2 + [ 5- 1]^2}

DA=\sqrt{(-1)^2+4^2}\implies \boxed{DA=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Perimeter}}{\sqrt{10}~~ + ~~\sqrt{13}~~ + ~~2~~ + ~~\sqrt{17}}~~ \approx ~~ 12.89

8 0
2 years ago
Janelle ate 4/5 of her graham cracker. Paul ate 3/5 of his graham cracker. The graham crackers were the same size.
sergij07 [2.7K]
1/5 less than janelle
6 0
3 years ago
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