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Leya [2.2K]
3 years ago
13

Can you please explain how i can work through these problems?

Mathematics
1 answer:
pshichka [43]3 years ago
3 0
Did you add a photo? I cant see one
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A gaint kite is contrstrused using bamboo for the edges and diagonals and card for sail. When mapped on the diagram, the ends ar
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Rip king Von the only rapper that rapped abt things that mattered
3 0
3 years ago
Loin has read 25 % of a book. If she has been reading for 5 hours, how many more hours will it take her to complete the book?
Anon25 [30]
Well, the answer is 15 hours

Explanation:
Since it took Loin 5 hours to read 25% of the books and the entire book is 100%, 25% is 1/4 of the book. We add on 5 hours to every 1/4 of the book so 1/2=10 hours, 3/4= 15 hours and the entire book =20 hours. So the entire book would take 20 hours to read but the question is How many MORE hours so we subtract 5 hours from 20 hours which equals 15.
4 0
3 years ago
A population of 400 beetles grows by 5% each week. How can the beetle population be determined after a number of weeks, w?
Helga [31]
For this case we have an equation of the form:
 f (w) = A * (b) ^ w
 Where,
 A: initial amount
 b: growth rate
 w: number of weeks
 Substituting values we have:
 f (w) = 400 * (1.05) ^ w
 Answer:
 the beetle population can be determined after a number of weeks, w, with the following function:
 
f (w) = 400 * (1.05) ^ w
6 0
3 years ago
Read 2 more answers
PLEASE HELP, I don’t know how to do this...like at all
Svet_ta [14]

Answer:

arc ? = 255°

Step-by-step explanation:

arc DB = 180° - 75° = 105°

arc ? = 360° - 105° = 255°

6 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
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