16
Explanation:
Okay so Jack started with 50 chocolates, and ended with 2.
The simple way to calculate it would be by realising that Jack only distributed 48 chocolates. We can find how many times 3 fits into 48 by dividing <span>48÷3=16</span>.
Using algebra, we substitute the value we want to find with x. Here what we want to find is the number of friends that were at Jack's party.
We know that he started with 50 chocolates, then distributed <span>3×</span> the number of friends present (which is x).
We write that down as <span>50−3x</span>
(It's minus because when chocolates are distributed, Jack is taking away from what he has.)
We know that after this, there were only 2 chocolates left, so it's
<span>50−3x=2</span>
Then we proceed by moving all the numbers to the right until only x is left:
<span>−3x=2−50</span>
<span>−3x=−48</span>
<span>x=<span><span>−48</span><span>−3</span></span></span>
<span>x=16</span>
Conclusion: The number of people that attended the party was 16
69 is the answer . (34)- (-35)
Answer:
i am good and really tired
Step-by-step explanation:
Answer:
what was the first one.....the first song part
Step-by-step explanation:
Confused what the question is. Are you looking for the product or the zeroes?
If you are looking for the product, then:
Use foil to get: sec²(1) - sec²(-csc²) -1(1) -1(-csc²)
= sec² + sec²csc² - 1 + csc²
= sec²csc² + sec² + csc² - 1
= sec²csc² + 1 - 1 (NOTE: sec² + csc² = 1 is an identity)
= sec²csc²
Answer: sec²csc²
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If you are looking for the zeroes, then:
Using the zero product property, set each factor equal to zero and solve.
<u>First factor:</u>
sec²Θ - 1 = 0
sec²Θ = 1
secΘ = 1, -1
remember that secΘ is 
= 1 = -1
cross multiply to get:
cosΘ = 1 cosΘ = -1
use the unit circle (or a calculator) to find that Θ = 0 and π
<u>Second factor:</u>
1 - csc²Θ = 0
1 = csc²Θ
1, -1 = cscΘ
remember that cscΘ is 
= 1 = -1
cross multiply to get:
sinΘ = 1 sinΘ = -1
use the unit circle (or a calculator) to find that Θ = 
and 
Answer: 0, π, ,
