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Cerrena [4.2K]
2 years ago
12

If an orthocenter lies inside of a triangle, then the triangle must be

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
8 0

Answer:

<h2><u><em>acute</em></u></h2>

Step-by-step explanation:

Remember :the orthocenter of  a triangle is the point of concurrency of the 3 altitudes.

\large \text{If an orthocenter lies inside of a triangle, then the triangle must be}\ :\\\\\large isosceles. \\\\\large obtuse. \\\\\large right. \\\\\large acute \checkmark

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Which function below is the inverse of f(x) = x2 − 16?
slega [8]
f(x) = x^{2} - 16
y = x^{2} - 16
x = y^{2} - 16
x + 16 = y^{2}
\±\sqrt{x + 16} = \sqrt{y^{2}}
\±\sqrt{x + 16} = y
\±\sqrt{x + 16} = f^{-1}(x)
4 0
3 years ago
A coffee business sells a pound of coffee for $ 9.75. Monthly expenses are $ 4,500 plus $ 4.25 for every pound of coffee sold. a
hram777 [196]

Answer:

a. IT = 9.75 * X

b. GT = 4500 + 4.25 * X

c. G = 9.75 * X - 4500 - 4.25 * X

Step-by-step explanation:

With the data of the statement we can get a function. Let X be the number of pounds sold.

to. Monthly income

IT = 9.75 * X

b. Monthly expenses

GT = 4500 + 4.25 * X

c. Monthly Earnings (Monthly Income - Monthly Expenses)

G = 9.75 * X - (4500 + 4.25 * X)

G = 9.75 * X - 4500 - 4.25 * X

4 0
3 years ago
Matt has answered 20/25 of the question on a test . What percent of test Questions has Matt answers
sergey [27]

you need to make the fraction to 100

100/25=

you multiply 20x4

80

6 0
3 years ago
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Factor this expression completely, then place the factors in the proper location on the grid. (Hint: First, factor using differe
Anna [14]

Answer: x= y =

Step-by-step explanation:

3 0
2 years ago
A pilot flew a 400 mile flight in 2.5 hours flying into the wind. Flying the same rate and with the same wind speed the return t
eduard

Answer: 20 mph

Explanation:

Speed is a physical quantity which is equal to the ratio between the distance covered (d) and the time taken (t):

v=\frac{d}{t}

In the first part of the problem, the plane flew a distance of d=400 mi in a time of t=2.5 h. The speed of the plane in this case was the difference between the proper speed of the plane, v, and the speed of the wind, w, since the plane flew opposite to the wind. So we can write:

v-w=\frac{400mi}{2.5h}=160 mph (1)

During the return trip, the plane flew with a speed (v+w), since the wind was on the tail, and it took 2 hours to cover the same distance:

v+w=\frac{400 mi}{2 h}=200 mph (2)

So we have two equations with two unknown variables. From (1), we get

v=160+w

Substituting into eq.(2)

(160+w)+w=200\\160+2w=200\\2w=40\\w=20 mph

So, the speed of the wind was 20 mph.

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3 years ago
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