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andrezito [222]
2 years ago
13

A department store wraps gifts for its customers. What is the amount of wrapping paper it would take to wrap a gift box with a w

idth of 8 inches, a height of 6 inches, and a length of 5 inches?
Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
8 0

Answer:236\ in.^2

Step-by-step explanation:

Given

Dimension of gift box is

Width b=8\ in.

height h=6\ in.

Length L=5\ in.

So, box is in shape cubiod

and its surface area is given by

S.A.=2(lb+bh+hl)

S.A.=2(5\times 8+8\times 6+6\times 5)

S.A.=2(40+48+30)

S.A.=2\times 118

S.A.=236\ in.^2

So, 236\ in.^2 of gift paper is required

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Find the value of x.
Nostrana [21]

Answer:

21.6 degrees

Step-by-step explanation:

the sum of angles in a triangle is 180 degrees

71 + x + (4x-11) = 180

open the brackets

71 + x +4x - 1 = 180

71 + 1 + x + 4x =180

72 + 5x =180

5x = 180 -72

5x = 108

x = 108/5 = 21.6

4 0
3 years ago
What is 156 divided by 12?
madreJ [45]
The answer for your question is thirteen
7 0
3 years ago
Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
you are lying 120 ft away from a tree that is 50 feet tall you look up at the top of the tree approxmaelty how far is your head
Pepsi [2]
Check the picture below.

5 0
3 years ago
(a) Tom says that 1/5 + 7/20 = 8/25
mezya [45]

numerator = top part of the fraction

denominator = bottom part of the fraction

* means multiply

a.

you can only add the numerator when the denominator is the same

cant add the denominator

denominator has to be the same

1/5 = 4/20

4/20 + 7/20 = 11/20

b.

1 7/8 = 15/8

3/4 ÷ 15/8 =

3/4 * 8/15 =

24/60 = divide both top and bottom by 12 =

2/5

7 0
3 years ago
Read 2 more answers
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