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andrezito [222]
2 years ago
13

A department store wraps gifts for its customers. What is the amount of wrapping paper it would take to wrap a gift box with a w

idth of 8 inches, a height of 6 inches, and a length of 5 inches?
Mathematics
1 answer:
Dennis_Churaev [7]2 years ago
8 0

Answer:236\ in.^2

Step-by-step explanation:

Given

Dimension of gift box is

Width b=8\ in.

height h=6\ in.

Length L=5\ in.

So, box is in shape cubiod

and its surface area is given by

S.A.=2(lb+bh+hl)

S.A.=2(5\times 8+8\times 6+6\times 5)

S.A.=2(40+48+30)

S.A.=2\times 118

S.A.=236\ in.^2

So, 236\ in.^2 of gift paper is required

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Alex787 [66]

Answer:

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Step-by-step explanation:

Applying the sine theorem:

WV/sin(X) = XV/sin(W)

=> WV = XV*sin(X)/sin(W) = 37*sin(50)/sin(63) = 31.81

Angle V = 180 - X - W = 180 - 50 - 63 = 67

Denote WH is a height of the triangle VWX, H lies on XV

=> WH = WV*sin(V) = 31.81*sin(67) =  29.28

=> Area of triangle VWX is calculated by:

S = side*height/2 = XV*WH/2 = 37*29.28/2 = 541.7 (m2)

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