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andrezito [222]
3 years ago
13

A department store wraps gifts for its customers. What is the amount of wrapping paper it would take to wrap a gift box with a w

idth of 8 inches, a height of 6 inches, and a length of 5 inches?
Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
8 0

Answer:236\ in.^2

Step-by-step explanation:

Given

Dimension of gift box is

Width b=8\ in.

height h=6\ in.

Length L=5\ in.

So, box is in shape cubiod

and its surface area is given by

S.A.=2(lb+bh+hl)

S.A.=2(5\times 8+8\times 6+6\times 5)

S.A.=2(40+48+30)

S.A.=2\times 118

S.A.=236\ in.^2

So, 236\ in.^2 of gift paper is required

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Find the distance between points M(-1,-10) and (-12,-3). round to the nearest tenth
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The formula of the distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (-1, -10) and (-12, -3). Substitute:

d=\sqrt{(-12-(-1))^2+(-3-(-10))^2}=\sqrt{(-11)^2+7^2}=\sqrt{121+49}=\sqrt{170}

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Answer: d ≈ 13.0

4 0
4 years ago
A random sample of 16 statistics examinations was taken. The average sample score was 76.2 with a sample variance of 144. The 99
dlinn [17]

99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

mean = 76.2

variance = 144

sd = sqrt(variance) = sqrt(144) = 12

n = 16

Degree of freedom (df) = n - 1 = 16- 1 = 15

Confidence level (C) = 99% = 0.99

Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 15 df and 1% significance level is 2.95

The margin of error will be:-

E = t×sd/√n = 2.95 ×  12/√16 = 8.85

The interval will be:-

Lower limit = mean - E = 76.2 - 8.85 = 67.35

Upper limit = mean + E = 76.2 + 8.85 = 85.05

Therefore, the 99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

To know more about margin of error follow

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