C3H8 + 5O2 -> 3CO2 + 4H20
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It is given in the question that 200.0 grams of sodium hydroxide reacts with excess of sulphuric acid.
The given reaction is shown below
In this reaction, two mole of sodium hydroxide react with one mole of sulphuric acid to give two mole of water and one mole of sodium sulfate.
To determine the mass of sodium sulfate, first calculate the moles of sodium hydroxide as the value of mass is provided.
The molecular weight of NaOH is 40 g/mol.
The formula is shown below.
Where,
✫ n is the number of moles
✫ m is the mass
✫ M is the molecular weight
To calculate the number of moles, substitute the values in the above equation.
In the equation it is given that 2 mole of sodium hydroxide gives 1 mole of sodium sulphate.
So, to determine the actual mole of sodium sulfate divide the calculated moles of NaOH by 2.
So 2.5 mol sodium sulfate is formed from 5 mol NaOH.
The molecular weight of sodium sulfate is 142.1 g/mol.
To calculate the mass of sodium sulfate, substitute the values in the formula.
Therefore, the mass of sodium sulfate formed when we start with 200.0 grams of sodium hydroxide and you have excess sulphuric acid is 355.25g.
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Answer:
Explanation:
Mass and weight are quite different terms .
Weight is defined as the amount of force exerted on the earth due to our mass and gravity of acceleration.
Given that the mass is 90 kg and gravity of acceleration of earth is 9.82 m/s^2.
So weight will be
So this is the weight of the 90kg man standing on earth.