Answer:
357.475
Explanation:
First you need periodic table and you have to look for mass
Fe = 3 x 55.845 = 167.535
P = 2 x 30.97 = 61.94
o = 4 x 2 so 8 oxygen = 8 x 16 = 128
add all and you get 357.475
Q = 1.161 J/kg of heat is required to melt 99.9 g of solid acetic acid (HCH,CO2). Q = mL(Latent heat is the energy emitted or absorbed by a body while changing it state ). (Latent heat is the energy released or absorbed by a body while changing it state ).
<h3>How to fix?</h3>
Apply the equation Q = mL where:
Energy is Q. (J)
m = Mass (g)
L = Acetic acid's latent heat of fusion 192(J/g) = J/g
Q is equal to 0.099 kg times 11.73 kj/mol.
Q = 1.161J/kg.
<h3>What is latent heat, and what varieties are there?</h3>
Latent heat is the amount of energy that a substance experiencing a change in state, such as ice turning into water or water turning into steam, can absorb or release while maintaining a constant temperature and pressure. Types: The material exists in three states: solid, liquid, and gaseous.
<h3>What does "sensible heat" mean?</h3>
Heat that can actually be felt is considered to be sensible heat. Instead of the phase shifting, energy is what causes the temperature to vary as it moves from one system to another. For instance, it warms the water instead of melting the ice.
Learn more about specific heat on:
brainly.com/question/11297584
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It is very camouflaged this way it will survive longer then most other animals
<h3>Answer:</h3>
Limiting reactant is Lithium
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of Lithium as 1.50 g
- Mass of nitrogen is 1.50 g
We are required to determine the rate limiting reagent.
- First, we write the balanced equation for the reaction
6Li(s) + N₂(g) → 2Li₃N
From the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Second, we determine moles of Lithium and nitrogen given.
Moles = Mass ÷ Molar mass
Moles of Lithium
Molar mass of Li = 6.941 g/mol
Moles of Li = 1.50 g ÷ 6.941 g/mol
= 0.216 moles
Moles of nitrogen gas
Molar mass of Nitrogen gas is 28.0 g/mol
Moles of nitrogen gas = 1.50 g ÷ 28.0 g/mol
= 0.054 moles
- According to the equation, 6 moles of Lithium reacts with 1 mole of nitrogen.
- Therefore, 0.216 moles of lithium will require 0.036 moles (0.216 moles ÷6) of nitrogen gas.
- On the other hand, 0.054 moles of nitrogen, would require 0.324 moles of Lithium.
Thus, Lithium is the limiting reagent while nitrogen is in excess.
