All categories

2 years ago

PLEASE HELP W A SERIOUS ANSWER! Question 3

Chemistry

2 answers:

bogdanovich [222]2 years ago

3 0

Answer:

Advantage: Very low fuel costs.

Advantage: Produces no polluting gases.

Disadvantage: Large-scale accidents can be catastrophic.

Disadvantage: Public perception of nuclear power is negative.

Explanation:

Bad White [126]2 years ago

3 0

Answer:

Advantage: Very low fuel costs.

Advantage: Produces no polluting gases.

Disadvantage: Large-scale accidents can be catastrophic.

Disadvantage: Public perception of nuclear power is negative.

Explanation:

You might be interested in

Can you help me on my science

svetlana [45]

Sbbsieoeoe9199wow9w9ww9w99w9

8 0

3 years ago

You placed 43.1 g of an unknown metal at 100 °C into a coffee cup calorimeter that contained 50.0 g of water that was initially

nika2105 [10]

Answer :

(a) The heat released by the metal is -312.48 J

(b) The specific heat of the metal is $0.0944J/g^oC$

Explanation :

For part A :

Heat released by the metal = Heat absorbed by the calorimeter + Heat absorbed by the water

$q=[q_1+q_2]$

$q=[c_1\times \Delta T+m_2\times c_2\times \Delta T]$

where,

q = heat released by the metal

$q_1$ = heat absorbed by the calorimeter

$q_2$ = heat absorbed by the water

$c_1$ = specific heat of calorimeter = $51.5J/^oC$

$c_2$ = specific heat of water = $4.184J/g^oC$

$m_2$ = mass of water = 50.0 g

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-22.0=1.2^oC$

Now put all the given values in the above formula, we get:

$q=[(51.5J/^oC\times 1.2^oC)+(50.0g\times 4.184J/g^oC\times 1.2^oC)]$

$q=312.48J$

Thus, the heat released by the metal is -312.48 J

For part B :

$q=m\times c\times \Delta T$

q = heat released by the metal = -312.48 J

m = mass of metal = 43.1 g

c = specific heat of metal = ?

$\Delta T$ = change in temperature = $(T_{final}-T_{initial})=23.2-100=76.8^oC$

Now put all the given values in the above formula, we get:

$-312.48J=43.1g\times c\times 76.8^oC$

$c=0.0944J/g^oC$

Thus, the specific heat of the metal is $0.0944J/g^oC$

8 0

3 years ago

How do scientist classify newly discovered organisms into domains and kingdoms? (6th Grade)

olga55 [171]

Answer: Scientists look for cell types, the ability to make food, number of cells in their bodies.

Explanation: Scientists look for cell types, the ability to make food, number of cells in their bodies when placing newly-discovered organisms.

5 0

2 years ago

An air mattress is filled with 0.55 moles of air. The air inside the mattress has a temperature of 295 K and a gauge pressure of

Nitella [24]

Answer: 385.4132857

Explanation:

Using the equation, PV=nRT, you can solve this problem.

P= 3.5 kPa V=? n= 0.55 moles of air T= 295K R= 8.314 (L kPa/mol K)

We use the constant rate of 8.314 because we are using kilopascals in this problem.

Using simple algebra we get-

V = (0.55 moles)(8.314 L kPa/mol k)(295 K) / 3.5 kPa

Using the calculator, we would get the answer of 385.4132857 L.

And whatever the significant figure is asked for, for example, 3 significant figures: the answer would be 385 liters.

3 0

3 years ago

Please help with this, i don't really get how to do this

LuckyWell [14K]

#4 and #5:
To find pH given concentration of H+ or H30+
pH = - log (H+ or H30+ M)

To find pH given concentration of OH-
Since you already found the pH for this (in #4), you subtract #4's answer from 14.
14 - (pH) = pOH

8 0

3 years ago