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Tcecarenko [31]
3 years ago
14

y = (x-16)2 A. Shift the graph of y = x2 down 16 units. B. Shift the graph of y= x2 right 16 units. C. Shift the graph of y = x2

left 16 units. D. Shift the graph of y = x2 up 16 units.
Chemistry
1 answer:
Ugo [173]3 years ago
3 0

Answer:

Uhmm i think i dont know the sent r 6un Dury r in eyeing in d7ue

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In general, sound travels faster through
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To answer the question "What is amplitude?", first look at the context of the question. A poem is also given before the questions which discusses about sound waves. Therefore, considering the context above, amplitude is the height of the wave. 
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3 years ago
A student obtains a 10.0g sample of a white powder labeled as BaCl2. After completely dissolving the powder in 50.0mL of distill
LekaFEV [45]

Answer:

Whether barium chloride solution was pure

Explanation:

We may answer whether barium chloride was pure. The sequence of this experiment might be depicted by the following balanced chemical equations:

BaCl_2 (aq)\rightarrow Ba^{2+} (aq) + 2 Cl^- (aq)

Ba^{2+} (aq) + SO_4^{2-} (aq)\rightarrow BaSO_4 (s)

Having a total sample of 10.0 grams, we would firstly find the mass percentage of barium in barium chloride:

\omega_{Ba^{2+}} = \frac{M_{Ba}}{M_{BaCl_2}} = \frac{137.327 g/mol}{208.23 g/mol\cdot 100\% = 65.95 \%

This means in 10.0 g, we have a total of:

m_{Ba^{2+}} = 10.0 g\cdot 0.6595 = 6.595 g of barium cations.

The precipitate is then formed and we measure its mass. Having its mass determined, we'll firstly find the percentage of barium in barium sulfate using the same approach:

\omega_{Ba} = \frac{137.327 g/mol}{233.38 g/mol}\cdot 100\% = 58.84 \%

Multiplying the mass we obtained by the fraction of barium will yield mass of barium in barium sulfate. Then:

  • if this number is equal to 6.595 g, we have a pure sample of barium chloride;
  • if this number is lower than 6.595 g, this means we have an impure sample of barium chloride, as we were only able to precipitate a fraction of 6.595 g.
3 0
3 years ago
You have 200 g of a substance with a molar mass of 150 g/mol. How many moles of the substance do you have? 0.75 mol 1.00 mol 1.3
tigry1 [53]

Answer:

Explanation:

200 g/150 g/mol = 1.33 mol

7 0
3 years ago
The formation of which product(s) will most likely be observed in a combustion reaction?
lianna [129]

Answer:

The formation of AN OXIDE

Explanation:

A combustion reaction is a chemical reaction which involves the burning of an hydrocarbon in oxygen

7 0
4 years ago
Read 2 more answers
Determine if the following statements are true or false. True Standard reduction potential is an intensive property True Reducti
tensa zangetsu [6.8K]

Answer:

Standard reduction potential is an intensive property---- True

Reduction takes place at the anode ----- False

The half reaction with the lower standard reduction potential will be at the cathode in a galvanic cell ------false

The half reaction with the higher standard reduction potential will be at the cathode in a galvanic cell  ------  True

Explanation:

An intensive property is a property of a substance which is inherent in it and part of its nature. It does not depend on the amount of substance present in the substance. Standard reduction potential is an intensive property.

In a galvanic cell, oxidation takes place at the anode and reduction takes place at the cathode. At the anode, the electrode potential is more negative (an oxidation) while at the cathode the reduction potential is less negative (a reduction).

4 0
3 years ago
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