Question

Help me solve this algebra equation

Answer 1

Answer:

Perimeter = $16\sqrt{5}$

Area = $80$

Step-by-step explanation:

To find the perimeter of the square, you can use the square perimeter formula, $P=4a$, where $a$ is equal to the length of one side:

$P=4a$

$P=4(4\sqrt{5})$

$P=16\sqrt{5}$

Then, to find the area of the square, you can use the square area formula, $A=a^2$, where $a$ is equal to the length of one side:

$A=a^2$

$A=(4\sqrt{5})^2$

$A=80$

Therefore, the perimeter of the square is $16\sqrt{5}$ millimeters and the area of the square is $80$ square millimeters.

I hope this helps!