Answer:
<em>AB = 5√2</em>
<em>AC = √145</em>
<em>BC = √65</em>
Step-by-step explanation:
Using the formula for calculating the distance between two points
D = √(x2-x1)²+(y2-y1)²
For AB A(-3,6),B(2,1),
AB = √(2+3)²+(1-6)²
AB = √(5)²+(-5)²
AB = √25+25
AB = √50
<em>AB = 5√2</em>
For AC A(-3,6) and C(9,5)
AC = √(9+3)²+(5-6)²
AC = √(12)²+(-1)²
AC = √144+1
<em>AC = √145</em>
For BC B(2,1), and C(9,5)
BC = √(9-2)²+(5-1)²
BC = √(7)²+(4)²
BC = √49+16
<em>BC = √65</em>
<em></em>
<em>Since All the sides are difference, hence triangle ABC is a scalene triangle</em>
The vertex form of the function is y = (x + 8)² - 71
The vertex is (-8 , -71)
Step-by-step explanation:
The vertex form of the quadratic equation y = ax² + bx + c is
y = a(x - h)² + k, where
- (h , k) are the coordinates of the vertex point
- a, b, c are constant where a is the leading coefficient of the function (coefficient of x²) , b is the coefficient of x and c is the y-intercept

- k is the value of y when x = h
∵ y = x² + 16x - 7
∵ y = ax² + bx + c
∴ a = 1 , b = 16 , c = -7
∵ 
∴ 
∴ h = -8
To find k substitute y by k and x by -8 in the equation above
∵ k is the value of y when x = h
∵ h = -8
∴ k = (-8)² + 16(-8) - 7 = -71
∵ The vertex form of the quadratic equation is y = a(x - h)² + k
∵ a = 1 , h = -8 , k = -71
∴ y = (1)(x - (-8))² + (-71)
∴ y = (x + 8)² - 71
∵ (h , k) are the coordinates of the vertex point
∵ h = -8 and k = -71
∴ The vertex is (-8 , -71)
The vertex form of the function is y = (x + 8)² - 71
The vertex is (-8 , -71)
Learn more:
You can learn more about quadratic equation in brainly.com/question/9390381
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Answer:
ummmmm nobody here speaks that language
Yes that’s correct. I’m doing flvs too!