Answer:
Cos ∅ = 3/5
BUT COSINE IS NEGATIVE IN THE SECOND QUADRANT.
Thus cos∅= -3/5
For this case, we must clear variable "x" from the given equation, expressed in terms of "a".
We have:
3/a x-4=20
By clearing "x" we have:
Adding 4 to both sides of the equation:
3/a x = 20 + 4
Multiplying by a/3 on both sides of the equation:
x=24a/3
x=8a
So, x=8a
Answer:
x=8a
Answer:
3.68 inches × 77.28 inches
Step-by-step explanation:
Given that,
The perimeter of a rectangle is 162 inches.
Let the width is b.
ATQ,
Length = 7 times than 3 times the width
l = 7(3b) = 21b ...(1)
The perimeter of a rectangle is given by :
P = 2(l+b)
Put all the values,
162 = 2(21b+b)
81 = 22b
b = 3.68 inches
Put the value of b in equation (1)
l = 21b
= 21 (3.68)
= 77.28 inches
Hence, the dimensions of the rectangle are 3.68 inches × 77.28 inches
Answer:
the correct answer is 1,272 bottles
Step-by-step explanation:
24x53=1,272
First option: correct. This is because angles WOX and XOZ are supplementary, so

Second option: correct. By the inscribed angles theorem, we have

Angles WOX and YOZ are congruent because they form a vertical pair; they both have measure 76 degrees. This means angles WXY and WZY are also congruent, since the interior angles of any triangle sum to 180 degrees in measure. Therefore triangles WXO and YZO form a side-side-side pair, and all SSS triangles are similar.
Third option: not correct. There is a theorem (not sure what the name is) regarding intersecting chords that asserts the average of the measures of arcs WY and XZ is the same as the measure of angle XOZ. This means

Fourth option: not correct. This is because arcs WX and XZ are not "supplementary" in the sense that they do not form a semicircle and their measures do not add to 180 degrees. We know this because it's clear that point O is not the center of the circle. If it was, then angle XOZ would be a central angle and its measure would be the same as the arc XZ it subtends.
Fifth option: correct. The theorem mentioned in the assessment of the third option makes itself useful here. We have
