Question

The perimeter of a rectangle is 120 meters and the length is 20 meters longer than the width. Find the dimensions of the rectangle. Let x = the length and y = the
2+2y = 12)
width. The corresponding modeling system is 2x + 2y =120 x-y = 20
Solve the system graphically

Answer 1

The dimension of the rectangle is 40meters by 20meters

What is the perimeter of a figure?

The perimeter of a figure is the sum of all the external sides of the figure

The formula for calculating the perimeter of rectangle = 2(l+w)

If the length is 20 meters longer than the width, then;

l = 20 + w

Substitute

120 = 2(20+2w)

60 = 20 + 2w

30 = 10 + w

w = 20 meters

Since l = 20  + w

l = 20 + 20

l = 40 meters

Hence the dimension of the rectangle is 40meters by 20meters

Learn more on perimeter of figure here: brainly.com/question/22447290