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Mila [183]
2 years ago
8

The perimeter of a rectangle is 120 meters and the length is 20 meters longer than the width. Find the dimensions of the rectang

le. Let x = the length and y = the
2+2y = 12)
width. The corresponding modeling system is 2x + 2y =120 x-y = 20
Solve the system graphically
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
8 0

The dimension of the rectangle is 40meters by 20meters

<h3>What is the perimeter of a figure?</h3>

The perimeter of a figure is the sum of all the external sides of the figure

The formula for calculating the perimeter of rectangle = 2(l+w)

If the length is 20 meters longer than the width, then;

l = 20 + w

Substitute

120 = 2(20+2w)

60 = 20 + 2w

30 = 10 + w

w = 20 meters

Since l = 20  + w

l = 20 + 20

l = 40 meters

Hence the dimension of the rectangle is 40meters by 20meters

Learn more on perimeter of figure here: brainly.com/question/22447290

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A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it
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Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, h_o=5\ ft

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

h=-16t^2+vt+h_0

Putting all the values,

h=-16t^2+60t+5 .....(1)

For maximum height, put

\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s

Put t = 1.875 in equation (1)

h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m

So, the maximum height reached by the ball is 61.25 m.

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3 years ago
How far is the point (12, 5) from the origin
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O comprimento de um retângulo é 6x e sua largura é 5y. A) Escreva uma expressão algébrica que representa o perímetro desse retân
Kobotan [32]

Answer:

A) 12x + 10y

B) 118cm

Step-by-step explanation:

A) A fórmula para calcular o perímetro de um retângulo é dada como:

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

Onde

L = comprimento do retângulo

W = largura do retângulo

A) A pergunta nos diz que:

O comprimento de um retângulo é 6x e sua largura é 5y.

A expressão algébrica que representa o perímetro do retângulo =

Perímetro de um retângulo = 2 (L + W)

= 2L + 2W

L = 6x, W = 5y

= 2 (6x) + 2 (5y)

= 12x + 10y

A expressão algébrica que representa o perímetro do retângulo é

P = 12x + 10y

B) Se x = 4 cm e y = 7 cm, qual é o valor numérico desse perímetro.

P = 12x + 10y

x = 4cm

y = 7cm

Perímetro = 12 (4) + 10 (7)

Perímetro = 48cm + 70cm

Perímetro do retângulo = 118cm

Portanto, o valor numérico do perímetro é 118cm

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