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2 years ago

What is the length of the dotted line? round to the nearest hundredth. 2.50 in. 3.75 in. 5.00 in. 6.25 in.

Mathematics

1 answer:

dezoksy [38]2 years ago

8 0

The measure of the length of the dotted line is 3.75 inches. Then the correct option is B.

<h3>What is a hexagon?</h3>

The hexagon is a two-dimensional geometry with six sides. And the polygon's sides are all straight lines that are joined side by side.

The perimeter of the hexagon is 7.5 inches.

Then the length of the hexagon will be

$\rm 7.5 = 6x\\\\x \ \ = 1.25$

The length of the hexagon is 1.25 inches.

Then the diagonal length of the hexagon will be

y = 2 × 1.25

y = 2.5

The diagonal length of the hexagon is 2.5 inches.

Then the length of the dotted line is 3.75 inches.

More about the hexagon link is given below.

brainly.com/question/3295271

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Find the solution set of this inequality|10x+20| ≤10

Pavlova-9 [17]

Answer:

solution is

[-3,-1]

Step-by-step explanation:

we are given

$|10x+20|\leq 10$

Firstly, we will find critical values

so, let's assume it is equal

$|10x+20|= 10$

now, we can break absolute sign

For $|10x+20|= -(10x+20)$ :

$-(10x+20)= 10$

we can solve for x

$-10x-20= 10$

Add both sides by 20

$-10x-20+20= 10+20$

$-10x= 30$

Divide both sides by -10

and we get

$x=-3$

For $|10x+20|= (10x+20)$ :

$(10x+20)= 10$

we can solve for x

$10x+20= 10$

Subtract both sides by 20

$10x+20-20= 10-20$

$10x= -10$

Divide both sides by 10

and we get

$x=-1$

so, critical values are

$x=-3$

$x=-1$

now, we can draw a number line and locate these values

and then we can check inequality on each intervals

For $(-\infty,-3)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-5

$|10\times -5+20|\leq 10$

$|-50+20|\leq 10$

$30\leq 10$

so, this is FALSE

For $[-3,-1]$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=-2

$|10\times -2+20|\leq 10$

$|-20+20|\leq 10$

$0\leq 10$

so, this is TRUE

For $(-1,\infty)$ :

We can select any random value from this interval and plug that in inequality

and we get

we can plug x=0

$|10\times 0+20|\leq 10$

$|0+20|\leq 10$

$20\leq 10$

so, this is FALSE

so, solution is

[-3,-1]

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