What is the parallel slope to the line y = 2x - 3?
2 answers:
You might be interested in
<h3><u>Solution</u><u>:</u></h3>
Please find the photograph for the square root of 3.
- Firstly, you have to write 3 as 3. 00 00 00.
- Then we should find out the root of the perfect square which is less than 3. Here, 1 is the required perfect square root because 1 × 1 = 1 only which is less than 3.
- Now 3 - 1 = 2 and we are placing 2 zeros after it so that it will be 200. Now we have to add 1 with the divisor 1 which will be 2. Then we have to select a number to be placed beside this 2 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 200. We see that if we place 7 after 2 and multiply 27 with 7, we get 189 which is less than 200.
- Now 200 - 189 = 11 and we are placing 2 zeros after it so that it will be 1100. Now we have to add 7 with the divisor 27 which will be 34. Then we have to select a number to be placed beside this 34 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 1100. We see that if we place 3 after 34 and multiply 3 with 343, we get 1029 which is less than 1100.
- Now 1100 - 1029 = 71 and we are placing 2 zeros after it so that it will be 7100. Now we have to add 3 with the divisor 343 which will be 346. Then we have to select a number to be placed beside this 346 in such a way that if we multiply this combined number with the new number, then we will get a number which is less than 7100. We see that if we place 2 after 346 and multiply 2 with 3462, we get 6924 which is less than 7100.
- So, we will get the quotient as 1.732 (corrected to three places of decimal).
4√3
= 4 × 1.732
= 6.928
<h3><u>Answer:</u></h3><u>6</u><u>.</u><u>9</u><u>2</u><u>8</u>
Hope it helps
See the attached figure to better understand the problem
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is
the length of a diagonal of the cuboid is 13.75 cm
let
L-----> length side of the cuboid
W----> width side of the cuboid
H----> height of the cuboid
we know that
One edge of the cuboid has length 2 cm-----> <span>I'll assume it's L
so
L=2 cm
[volume of a cuboid]=L*W*H-----> 2*W*H
40=2*W*H------> 20=W*H-------> H=20/W------> equation 1
[surface area of a cuboid]=2*[L*W+L*H+W*H]----->2*[2*W+2*H+W*H]
100=</span>2*[2*W+2*H+W*H]---> 50=2*W+2*H+W*H-----> equation 2
substitute 1 in 2
50=2*W+2*[20/W]+W*[20/W]----> 50=2w+(40/W)+20
multiply by W all expresion
50W=2W²+40+20W------> 2W²-30W+40=0
using a graph tool------> to resolve the second order equation
see the attached figure
the solutions are
13.52 cm x 1.48 cm
so the dimensions of the cuboid are
2 cm x 13.52 cm x 1.48 cm
or
2 cm x 1.48 cm x 13.52 cm
<span>Find the length of a diagonal of the cuboid
</span>diagonal=√[(W²+L²+H²)]------> √[(1.48²+2²+13.52²)]-----> 13.75 cm
the answer is
the length of a diagonal of the cuboid is 13.75 cm