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Anarel [89]
3 years ago
9

A regular polygon has an odd number of sides. Which statement is true about the lines of reflection for the polygon that will ma

p the shape onto itself? A. Lines that connect pairs of opposite vertices are lines of reflection. B. The perpendicular bisectors for each side are the only lines of reflection. C The lines of reflection are parallel to the sides of the polygon. D There are no lines of reflection.
Mathematics
2 answers:
Alecsey [184]3 years ago
4 0
"The lines of reflection are parallel to the sides of the polygon" is the statement that <span>is true about the lines of reflection for the polygon that will map the shape onto itself. The correct option among all the options that are given in the question is the third option or option "C". I hope that the answer has helped you.</span>
Fiesta28 [93]3 years ago
3 0

Answer:  B. The perpendicular bisectors for each side are the only lines of reflection.


Step-by-step explanation:

A reflectional symmetry or line of symmetry divides a figure into two mirror-image equal halves.

For regular polygon with n sides, it has n line of symmetry.

If n is even then the lines that connect pairs of opposite vertices are lines of reflection.

If n is odd then the lines which passes through a vertex point and the mid point of the side opposite to it is the line of symmetry, and that lines are perpendicular bisector for side opposite to the vertex.

Thus, if n is odd then the perpendicular bisectors for each side are the only lines of reflection.

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Jim is showing his work in simplifying (−8.5 + 6.1) − 1.3.
dexar [7]

9514 1404 393

Answer:

  In step 4, Jim's answer is incorrect.

Step-by-step explanation:

In step 1, Jim swaps the order of addends using the commutative property of addition.

In step 2, Jim uses the distributive property to factor -1 from the final two terms. (The associative property lets Jim move parentheses.)

  6.1 +(-8.5 -1.3) . . . associative property

  6.1 +(-1)(8.5 +1.3) . . . distributive property

In step 3, Jim has used the properties of real numbers to form the sum of two of them.

In step 4, Jim wrote an answer of 1.1, when the answer should have been -3.7. Jim's answer is incorrect.

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The descriptive statements about steps 2 and 4 are both true.

8 0
3 years ago
The factorization below is missing two positive integers a and b. 6x^(3)+18x^(2)-240x=6x(x-a)(x+b) Factor the polynomial and the
Dvinal [7]

Answer:

a = 5

Step-by-step explanation:

Hello, please consider the following.

6x^3+18x^2-240x=6x(x^2+3x-40)\\\\\text{** The sum of the zeroes is -3=-8+5 and the product is -40=-8*5. **}\\\\\text{** So, we can factorise. **}\\\\6x^3+18x^2-240x=6x(x^2+3x-40)=6x(x^2+8x-5x-40)\\\\=6x(x(x+8)-5(x+8))\\\\\large \boxed{=6x(x+8)(x-5)}

So, a = 5.

Thank you.

7 0
4 years ago
1/2n-17/12=2/3n-13/6
emmasim [6.3K]
1/2/-33+2=62 but I d k
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4 years ago
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Find an equation for those points P such that the distance from P to A(0, 1, 2) is equal to the distance from P to B(6, 4, 2). W
suter [353]

Answer:  The required equation for points P is 4x+2y=17.

Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).

To find the equation for points P such that the distance of P from both A and B are equal.

We know that the distance between two points R(a, b, c) and S(d, e, f) is given by

RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.

Let the point P be represented by (x, y, z).

According to the given information, we have

PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.

Thus, the required equation for points P is 4x+2y=17.

8 0
3 years ago
A car dealer will sell you a used car for $6,898 with $798 down and payments of $169.51 per month for 48 months. What is
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Answer:

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Step-by-step explanalime boba no other

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3 years ago
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