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lions [1.4K]
3 years ago
10

A student estimated the sum

Mathematics
2 answers:
Natasha_Volkova [10]3 years ago
6 0

Answer:

i don"t know  if it right but i got 183.275

Step-by-step explanation:

i looked up the answer

m_a_m_a [10]3 years ago
4 0
It is incorrect because if those decimals were to be added together it would provide a different number
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The school cafeteria offered a choice of pizza or nachos to sixth-grade students. Seventy-seven students chose pizza.This repres
romanna [79]
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Read 2 more answers
It is known that x=7 is a root of the equation ax^2 + bx + 2= 0, where a<0. Solve the inequality ax²4 +bx^2 + 2>0.
kap26 [50]

Answer:

2/(7a) < x < 7

Step-by-step explanation:

The product of roots of ax² +bx +c is c/a. In this case, that means the second root of the equation is ...

... 2/(7a)

Since a < 0, the parabola opens downward and 2/(7a) < 0. The quadratic function will be positive between the two roots, on the interval ...

... 2/(7a) < x < 7

7 0
4 years ago
A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random.
DerKrebs [107]

corrected question:A jar contains two blue and five green marbles. A marble is drawn at random and then replaced. A second marble drawn at random. For each of the following, find the probability that: a) both marbles are blue b) both marbles are the same color  c)the marbles are different in color

Answer:

Step-by-step explanation:

<u><em>The probability was done with replacement.</em></u>

Probaility of an event happening=\frac{number of required outcomes}{number of possible outcomes}

number of blue marbles= 2

number of green marbles=5

total number of marbles=7

(a) probability that both marbles are blue = pr(first is blue)*pr(second is blue)

                                  =\frac{2}{7}*\frac{2}{7}

                                   =\frac{4}{49}

(b)probability that both marbles are the same color =pr(first is blue)*pr(second is blue) + Pr(first is green)*Pr(second is green)

   =\frac{4}{49} + \frac{5}{7}*\frac{5}{7}

   =\frac{4}{49} + \frac{25}{49}

 =\frac{29}{49}

(c)Probability that the marbles are different in colors=pr(first is blue)*pr(second is green) + Pr(first is green)*Pr(second is blue)

  =\frac{2}{7}*\frac{5}{7}+ \frac{5}{7}*\frac{2}{7}

           =\frac{10}{49}+\frac{10}{49}

      =\frac{20}{49}

6 0
3 years ago
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