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Reil [10]
3 years ago
9

Which equation has infinitely many solutions?

Mathematics
1 answer:
posledela3 years ago
4 0

the last one

Step-by-step explanation:

if you start solving and end up with all zero it's infinetly many

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Melissa collects data on her college graduating class. She finds out that of her classmates, 60% have brown hair, 20% have blue
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your answer is 0.75

Step-by-step explanation:

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Is there a cheating app to use to graph tangents
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You can user the application name Geogebra

Step-by-step explanation:

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0.8y+0.25= -0.4<br><br> Solve for y
disa [49]

Answer:

y = -13/16

Step-by-step explanation:

<u>Given:</u>

0.8y+0.25= -0.4

<u>To Find:</u>

Solve for y

<u>Solution:</u>

Multiply both sides by 100

0.8y\cdot \:100+0.25\cdot \:100=-0.4\cdot \:100

Simplify

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Subtract 25 from both sides

80y+25-25=-40-25

Simplify

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\frac{80y}{80}=\frac{-65}{80}

Simplify

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Thus, y = -13/16

or in decimal form it equal y = -0.8125

<u><em>~Lenvy~</em></u>

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Solve y=f(x) for x. Then find the input when the output is -3.
DochEvi [55]

Answer:

Please check the explanation

Step-by-step explanation:

Given the function

f\left(x\right)\:=\:\left(x-5\right)^3-1

Given that the output = -3

i.e. y = -3

now substituting the value y=-3 and solve for x to determine the input 'x'

\:\:y=\:\left(x-5\right)^3-1

-3\:=\:\left(x-5\right)^3-1\:\:\:

switch sides

\left(x-5\right)^3-1=-3

Add 1 to both sides

\left(x-5\right)^3-1+1=-3+1

\left(x-5\right)^3=-2

\mathrm{For\:}g^3\left(x\right)=f\left(a\right)\mathrm{\:the\:solutions\:are\:}g\left(x\right)=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}

Thus, the input values are:

x=-\sqrt[3]{2}+5,\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}-i\frac{\sqrt[3]{2}\sqrt{3}}{2},\:x=\frac{\sqrt[3]{2}\left(1+5\cdot \:2^{\frac{2}{3}}\right)}{2}+i\frac{\sqrt[3]{2}\sqrt{3}}{2}

And the real input is:

x=-\sqrt[3]{2}+5

  • x=3.74
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3 years ago
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