Question

Two planets are orbiting a star in a distant galaxy the first has a semimajor axis of 150 x 10^6 km an eccentricity of 0. 20 and a period of 1. 0 earth years

Answer 1

For two planets orbiting a star in a distant galaxy, having the first semimajor axis of 150 x 10^6 km,  the period of the second plane  is mathematically given as

T=2.2earth year

What is the period of the second planet?

Generally, the equation for the time period  is mathematically given as

$T^{2} \appox a^{3}$

Therefore, for planet one

$1^2\approx (150 x 10^6)^3$

In conclusion, For planet 2

T^2=(250/150)^3

T=√4.632

T=2.2earth year

Read more about Time

brainly.com/question/4931057

Answer 2

The period of the second planet for two planets circling a star in a faraway galaxy with a first semimajor axis of 150× 10⁶ km. The time period of the planet will be 2.2 earth years.

What is the time period of the revolution?

The time period of the revolution is the time required to complete one revolution. It is guven by T. It is measured in seconds.

The equation of the time period is found as;

$\rm T = \frac{250}{150} ^3 \\\\ T= \sqrt{4.632} \\\\ T=2.2 \ earth \ year$

Hence the time period of the planet will be 2.2 earth years.

To learn more about the time period of the revolution refer to the link;

brainly.com/question/15228034

#SPJ4