All categories

3 years ago

How is friction reduced between an air hockey puck and the table.

Physics

1 answer:

iren2701 [21]3 years ago

6 0

Answer:

An air hockey table has a very smooth and slippery surface which reduces friction by suspending the puck on cushion of air, so that this its motion is much less altered by friction, causing it to glide in a straight line at relatively constant velocity across the table.

Explanation:

You might be interested in

How can athletes promote social<br> justice?

CaHeK987 [17]

ORLANDO, Fla. —

The NBA playoffs will pick up again this weekend after players made a powerful statement on Wednesday.

Athletes have a voice when it comes to change and demands for social justice. Their impact is extending off the court and into the world.

"We stand with them, we support them and we're there for them," Michael-Carter Williams said.

The Orlando Magic's Michael Carter-Williams spoke Thursday about the Milwaukee Bucks' decision not to play Wednesday and instead, making a demand for the end to social injustice.

"We have a big platform that we can use to really make change in this country and we can go home to our communities and make change there," Carter-Williams said.

The Bucks' decision led to all NBA games being postponed Wednesday, some baseball games weren't played, as well as soccer, and the WNBA.

"This was a historic moment last night, we never had anything like that happen before," Dr. Richard Lapchick said.

Lapchick is a UCF professor who is also the president of the Institute for Sport and Social Justice.

He says the impact from Wednesday's boycott can't be overstated.

"The unity that occurred between the players and teams and leagues, was particularly impressive," Lapchick said. "The importance of what the players are doing, and what the country is doing in response, is looking at more than police brutality, it's looking at systemic racism."

"People are just tired of what's going on, there's no justice at all," Sandy Lallavee said.

Lallavee is one of the many residents we spoke to who supports the athletes' desire for a committed dialogue and effective change.

"I think it's the right thing to do right now, I support their decision and I think it's terrible what's happening in the world, in America," Gerrod Trytten said.

"It's a younger generation doing things and trying to make change, I respect them and I think they're doing the right thing," Nick Trapp said.

"They're showing their humanity, they're showing what they really care about in society," Lapchick said.

6 0

3 years ago

The magnitude of the Normal Force on a

lbvjy [14]

Answer:

5. Is greater than mg, always

Explanation:

If the cone has an inclination of angle β, the sum of forces will be:

x-axis (centripetal axis):

N*sin β = m*ax where ax is the centripetal acceleration

y-axis:

N*cos β - m*g = m*ay where ay is the vertical acceleration. If the block starts falling down, ay will be negative. If the block starts sliding up, ay will be positive. If the block does not move up nor down, ay=0.

Solving for N:

$N = \frac{m*g + m*ay}{cos \beta }$

If ay is positive or zero, N will be greater than mg. If ay is negative, N will be less than mg.

If the block is sliding along a horizontal circular path (not up, nor down), ay = 0, so N will always be greater than mg.

7 0

3 years ago

Light is incident on the left face of an isosceles prism; with an apex angle of 49o, such that the light exiting the right face

Sunny_sXe [5.5K]

Answer:

$\mu = 1.645$

Explanation:

By Snell's law we know at the left surface

$\theta_i = 19^o$

$\theta_r = ?$

$\mu_1 = 1$

$\mu_2 = \mu$

now we have

$1 sin19 = \mu sin\theta_r$

$0.33 = \mu sin\theta_r$

now on the other surface we know that

angle of incidence = $\theta_r'$

$\theta_e = 90$

so again we have

$\mu sin\theta_r' = 1 sin90$

so we have

$\theta_r = sin^{-1}\frac{0.33}{\mu}$

$\theta_r' = sin^{-1}\frac{1}{\mu}$

also we know that

$\theta_r + \theta_r' = 49$

$sin^{-1}\frac{0.33}{\mu} + sin^{-1}\frac{1}{\mu} = 49$

By solving above equation we have

$\mu = 1.645$

3 0

3 years ago

Read 2 more answers

A cyclotron designed to accelerate protons has a magnetic field of magnitude 0.15 T over a region of radius 7.4 m. The charge on

klio [65]

Explanation:

It is given that,

Magnetic field, B = 0.15 T

Charge on a proton, $q=1.60218\times 10^{-19}\ C$

Mass of a proton, $m=1.67262 \times 10^{-27}\ kg$

The cyclotron frequency is given by :

$f=\dfrac{qB}{2\pi m}$

$f=\dfrac{1.60218\times 10^{-19}\ C\times 0.15\ T}{2\pi \times 1.67262 \times 10^{-27}\ kg}$

f = 2286785.40 Hz

$\omega=14368296.44\ rad/s$

$\omega=1.43\times 10^7 rad/s$

Hence, this is the required solution.

8 0

3 years ago

A"car"initially"at"rest"experiences"a" constant"acceleration"along"a"horizontal" road."the"position"of"the"car"at"several" succe

marysya [2.9K]

In the process of peppering the question with those forty (40 !) un-necessary quotation marks, you neglected to actually show us the illustration. So we have no information to describe the adjacent positions, and we're not able to come up with any answer to the question.

7 0

3 years ago