Answer:
4th option because the two negatives will become positive and the 3rd will make it negative again
Answer:
x^2+y^2+z^2-10x-6y-10z +50 =0
Step-by-step explanation:
Given that a sphere is contained in the first octant
Centre of the sphere is given as (5,3,5)
Since this is contained only in the first octant radius should be at most sufficient to touch any one of the three coordinate planes
When it touches we can get the maximum sphere
We find that y coordinate is the minimum of 3 thus radius can be atmost 3 so that then only it can touch y =0 plane i.e. zx plane without crossing to go to the other octants.
Hence radius =3
Equation of the sphere would be

2(8-4)2-10/2, 8 - 4 is 4 so then times that by 2 and you'll get 8 then multiply that by 2 to get 16, after that you need to subtract it by ten which is 6 then divide it by 2 to get 3.
Hope this helped
Step-by-step explanation:
a = 5
b = -3
25 - -3/ -3 - 25
= 28 / -28
= -1
We make the composition of both functions:
f (x) = x ^ 2-1
g (x) = 2x-3
Then:
f (g (x)) = (2x-3) ^ 2-1
Rewriting:
f (g (x)) = 4x ^ 2-12x + 8
The domain of this function is all real numbers.
Equivalently
x: (-inf, inf)
answer:
x: (-inf, inf)
option 1.