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mr Goodwill [35]
2 years ago
13

PLS HELPPP WHAT IS THE ANSWER???

Mathematics
1 answer:
Juliette [100K]2 years ago
6 0

Answer:

plug in the values and you get

-4

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Simplify x2 + 5x + 4/<br> X + 4
DIA [1.3K]

Answer:

\frac{x3 + 5x2 + 4x + 4}{x}

Step-by-step explanation:

x2+5x+ 4/x+4

5 0
3 years ago
The measure of an angle is 81°. What is the measure of its complementary angle?
nataly862011 [7]

Step-by-step explanation:

Let its complementary angle be x.

So

81+x=90

so, x = 9.

so

complementary angle of 81° is 9°.

8 0
3 years ago
Point A is at (2,-8) and the point C is at (-4,7). Find the coordinates of point B on AC such that the ratio of AB to BC is 2:1.
pentagon [3]

Answer:

The coordinates of point B are (-2, 2)

Step-by-step explanation:

We have two points: A and C.

The coordinates for A are (2, -8) and the coordinates for C are (-4, 7).

We have to find the coordinates of the point B, that satisfies the condition that the distance AB is 2 times the distance BC.

We also know that B is a point of the line AC.

We can calculate the line AC as a linear function y=mx+b.

The slope m is:

m=\dfrac{y_c-y_a}{x_c-x_a}=\dfrac{7-(-8)}{-4-2}=\dfrac{15}{-6}=-2.5

Then, the y-intercept b can be calculated using the coordinates of one of the points, in this case point A:

y=-2.5x+b\\\\b=y_a+2.5x_a=-8+2.5*2=-8+5=-3

Then, we know that B is a point of the linear function y=-2.5x-3, within the range x ∈ (-4; 2).

To have a ratio AB to BC of 2 to 1, we can divide the length of the line AC in 3 parts, and the point B will be located in the  end of the segment nearer to point C.

In the picture attached, you can see the division of the segment AC in three parts and the location of point B=(x, y).

Applying the Thales theorem, we can divide the segment in the y-axis in three and calculate y, and the same for the x-axis.

Then, the coordinate y for the point B is:

y=y_c-(y_c-y_a)/3\\\\y=7-[7-(-8)]/3=7-15/3=7-5=2\\\\\\x=x_c-(x_c-x_a)/3\\\\x=-4-(-4-2)/3=-4-(-6)/3=-4+2=-2

Then, the point B has coordinates (-2, 2).

We can verify the distances as:

AB=\sqrt{(2-(-2))^2+((-8)-2)^2}=\sqrt{16+100}=\sqrt{116}\\\\\\BC=\sqrt{((-2)-(-4))^2+(2-7)^2}=\sqrt{4+25}=\sqrt{29}\\\\\\\dfrac{AB}{BC}=\dfrac{\sqrt{116}}{\sqrt{29}}=\sqrt{\dfrac{116}{29}}=\sqrt{4}=2

4 0
3 years ago
HELLLLLLPPPPPPPPPP.......... i asked some friends for help and they didn't really understand it.... And my teachers are confusin
dimulka [17.4K]
Hey there!

In this problem, we'll just be finding the surface area of a rectangular prism. In this example, a surface area is a sum of all the areas of each individual face. On this rectangular prism, we have 6 faces, and two of each kind. Our formula is:

SA = 2(lw + wh + lh)

Notice how it has a 2. That two is because those two variables just applies for one side, and there's two for each type of side. On this diagram, the rightmost side's area would be the width (32) times the height (49) and the product would be the area. Let's plug in our numbers:

SA = 2(41 * 32 + 32*49 + 41*49)

Multiply:

SA = 2( 1312 + 1568 + 2009) =

Add:

SA = 2(2880 + 2009)

SA = 2(4889)

SA = 9778 ft squared, or C.

Hope this helps!
7 0
4 years ago
Read 2 more answers
Colleen is selling tubs of popcorn to raise money for the school choir. Her goal is to raise $150. Colleen starts with 40 tubs o
Vanyuwa [196]
Goal: $150
3/4 of 40 : 30
30x3.75= $112.05
She still needs : $37 or $37.05
7 0
3 years ago
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