<span><span>1/2<span>(<span>2g−3</span>)</span></span>=<span>−<span>4<span>(g+1)</span></span></span></span>
<span><span>1/2<span>(<span>2g−3</span>)</span></span>=<span>−<span>4<span>(g+1)</span></span></span></span>
<span><span>g+<span>−3/2</span></span>=<span><span>−4g</span>−4</span></span>
<span><span><span>g+<span>−3/2</span></span>+4g</span>=<span><span><span>−4g</span>−4</span>+4g</span></span><span><span>5g+<span>−32</span></span>=−4</span>
5g+−3/2+3/2=−4+3/2
<span><span>
5g</span>=<span>−5/2</span></span>
<span><span>5g/5</span>=<span><span>−52</span>5</span></span><span>
g=<span>−1<span>2
Hoped I helped!</span></span></span>
Answer:
5x+2y=35
Step-by-step explanation:
Let me know if this is wrong.
Answer:
150 miles
Step-by-step explanation:
In this problem, we are only interested in the distance that Lauren drove, this means that her average speed (75 mph to the cost, and 25 mph on the way back) does not matter since the distance remains the same. If one leg of trip is 75 miles long, the total mileage for the round trip is:
Lauren drove 150 miles.
Complete question :
Two researchers, Jaime and Mariya, are each constructing confidence intervals for the proportion of a population who is left-handed. They find the point estimate is 0.13. Each independently constructed a confidence interval based on the point estimate, but Jaime’s interval has a lower bound of 0.097 and an upper bound of 0.163, while Mariya’s interval has a lower bound of 0.117 and an upper bound of 0.173. Which interval is wrong? Why?
Answer:
Mariya's interval
Step-by-step explanation:
Point estimate = 0.13
Mariya's confidence interval :
Lower boundary = 0.117
Upper boundary = 0.173
Jamie's confidence interval :
Lower boundary = 0.097
Upper boundary = 0.163
The correct confidence interval should have an average value equal to the value of the point estimate ;
Jamie's confidence interval average :
(0.097 + 0.163) / 2 = 0.26 / 2 = 0.13
Mariya's confidence interval average :
(0.117 + 0.173) / 2 = 0.29 / 2 = 0.145
Based on the confidence interval average obtained we can conclude that Mariya's interval is wrong as it the average obtained is greater than the point estimate.
0.145 > 0.13
