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Vladimir [108]
2 years ago
15

Can you find the slope -intercept equation of each line code ?​

Mathematics
1 answer:
ikadub [295]2 years ago
5 0

Answer:

You can find and write the equations in Slope-Intercept form due to the slope and y-intercept.

Step-by-step explanation:

The Slope-Intercept Form Formula: y=mx+b

The m represents the slope while the b represents the y-intercept

You can also use y2 - y1 / x2 - x1 to find the slope which is the m in your formula.

Lastly, to find a y-intercept, you can plug in your coordinate for the x and y to do two-step linear equations.

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Use the drop-down menus to complete each equation so the statement about its solution is true. I’ll give brainliest :))
melisa1 [442]

Step-by-step explanation:

5 - 4 + 7x + 1 = 7x + 2.

If there are no solutions, then it is of the form 7x + c, where c is any real number besides 2.

If there is 1 solution, then it is of the form mx + c, where m is any real number besides 7 and c is any real number.

If there are infinitely many solutions, then it is of the form 7x + 2.

3 0
3 years ago
If there is 15 liters of milk in the refrigerator, after how many days will more milk need to be purchased?
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Answer:

Depends on Howe much you can drink. It varies.

Step-by-step explanation:

7 0
3 years ago
Marco has 2 bags of flour with 6
zlopas [31]

Answer:

2 batches

Step-by-step explanation:

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2 years ago
What is the area of this triangle?
iragen [17]

Answer:

9

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou
Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let z be the

\displaystyle z = \frac{x - \mu}{\sigma}.

In this question, x = 5 and \sigma = 2. The equation becomes

\displaystyle z = \frac{5 - \mu}{2}.

To solve for \mu, the mean of this distribution, the only thing that needs to be found is the value of z. Since

The problem stated that P(X \le 5) = 69.85\% = 0.6985. Hence, P(Z \le z) = 0.6985.

The problem is that the normal distribution tables list only the value of P(0 \le Z \le z) for z \ge 0. To estimate  z from P(Z \le z) = 0.6985, it would be necessary to find the appropriate

Since P(Z \le z) = 0.6985 and is greater than P(Z \le 0) = 0.50, z > 0. As a result, P(Z \le z) can be written as the sum of P(Z < 0) and P(0 \le Z \le z). Besides, P(Z < 0) = P(Z \le 0) = 0.50. As a result:

\begin{aligned}&P(Z \le z)\\ &= P(Z < 0) + P(0 \le Z \le z) \\ &= 0.50 + P(0 \le Z \le z)\end{aligned}.

Therefore:

\begin{aligned}&P(0 \le Z \le z) \\ &= P(Z \le z) - 0.50 \\&= 0.6985 - 0.50 \\&=0.1985 \end{aligned}.

Lookup 0.1985 on a normal distribution table. The corresponding z-score is 0.52. (In other words, P(0 \le Z \le 0.52) = 0.1985.)

Given that

  • z = 0.52,
  • x =5, and
  • \sigma = 2,

Solve the equation \displaystyle z = \frac{x - \mu}{\sigma} for the mean, \mu:

\displaystyle 0.52 = \frac{5 - \mu}{2}.

\mu = 5 - 2 \times 0.52 = 3.96.

3 0
3 years ago
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