Answer: x ≥ 0
Step-by-step explanation:
First, let's define the symbols used:
a < x (this means that a is strictly smaller than x)
a > x (this means that a is strictly larger than x)
a ≤ x (this means that a is smaller than or equal to x)
a ≥ x (this means that a is larger than or equal to x)
Now we have the statement "x is no less than 0"
Then x can be equal to zero, or larger than zero, but never smaller than zero.
Looking at the symbols above, we know that we need to use:
x ≥ 0
(this is equivalent to the statement)
Answer:
In economics, a portfolio is a term for a specific set of stocks, bonds, shares, and other securities owned by an investor. In general, the investor seeks to compile and diversify a portfolio of securities that offers maximum profitability and at the same time is diverse, in order to minimize possible risks. In general, these types of portfolios are considered efficient, as they do not leave the investment risk tied to a single factor. However, these two goals often go against each other, so the composition of the portfolio means a certain compromise.
Answer: C on edge
Step-by-step explanation:
<h2>
Explanation:</h2>
Let's graph the equation:
Which is the red graph shown below. As you can see this is the pattern of the Absolute Value Function. In order to translate this graph 14 units up, let's add 14 to 
. In doing so we get the new function:
So we get a new graph which is the blue one. In order to prove that this is the correct translation, let's take the vertex of the red graph which is the origin. To translate this graph 14 units up implies that each point is shifted 14 units up, so for the vertex of the red graph:
So the new vertex matches the vertex of the blue graph. Finally, the equation for the translation of 14 units up is 
<h2>Learn more:</h2>
Horizontal and vertical shift: brainly.com/question/13774447#
#LearnWithBrainly
The space between the two spheres will be the volume of the larger sphere minus the volume of the smaller sphere. Given that the volume of any sphere is:
V=(4πr^3)/3 The space between to sphere of different radius and positioned about the same center is:
S=(4πR^3)/3-(4πr^3)/3 I used S=volume of space, R=larger radius and r=smaller radius...
S=(4π/3)(R^3-r^3), we are told that R=5 and r=4 so
S=(4π/3)(5^3-4^3)
S=(4π/3)(125-64)
S=(4π/3)(61)
S=244π/61
S=4π cm^3
S≈12.57 cm^3 (to nearest hundredth of a ml)
