We have that the freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01
![X=6.5-5](https://tex.z-dn.net/?f=X%3D6.5-5)
![X=1.5](https://tex.z-dn.net/?f=X%3D1.5)
From the question we are told
Calculate the freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01
Generally We Know that
Freezing Point of cyclohexane is 6.5ºC
Kf for cyclohexane is 20ºC/m
Density of cyclohexane is 0.779 g/mL
Generally the equation for the is mathematically given as
![C6H12_{mass} = 20 x 0.78 \\\\C6H12_{mass} = 15.6g](https://tex.z-dn.net/?f=C6H12_%7Bmass%7D%20%3D%2020%20x%200.78%20%5C%5C%5C%5CC6H12_%7Bmass%7D%20%3D%2015.6g)
Therefore
![Solution's\ Molality=\frac{0.6g }{154g}\\\\Solution's\ Molality = 0.25m](https://tex.z-dn.net/?f=Solution%27s%5C%20Molality%3D%5Cfrac%7B0.6g%20%7D%7B154g%7D%5C%5C%5C%5CSolution%27s%5C%20Molality%20%3D%200.25m)
Therefore
![\lambda= Cf\ x\ m\\\\\lambda= 20 x\ 0.25\\\\\lambda= 5](https://tex.z-dn.net/?f=%5Clambda%3D%20Cf%5C%20x%5C%20m%5C%5C%5C%5C%5Clambda%3D%2020%20x%5C%200.25%5C%5C%5C%5C%5Clambda%3D%205)
Therefore
The freezing point of 0.5g of biphenyl in 20.0mL of cyclohexane. Cyclohexane Fp = 6.5 Celsius Kf 20.01
![X=6.5-5](https://tex.z-dn.net/?f=X%3D6.5-5)
![X=1.5](https://tex.z-dn.net/?f=X%3D1.5)
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