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Leni [432]
3 years ago
8

What physical property does salt have when it is dissolved in water?

Chemistry
1 answer:
Mashutka [201]3 years ago
3 0
1-electrical charges

homogeneous mixture
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6969696969696969696696969696969+333333333x3333333333333
solniwko [45]

Answer:

my calculator said this

Explanation:

6.96969697E30

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:0

4 0
3 years ago
What is the basic unit for measuring length
scoundrel [369]

The answer is meter

8 0
4 years ago
Read 2 more answers
A solution has a hydronium concentration of 1.3x10^-3 M. what is the pH of the solution?​
Montano1993 [528]

Well, once you have done it and gotten back to us, which solution is more basic?

your answer- 6.65

5 0
4 years ago
What would be the new volume if the pressure on 600 L is increased from 90.0 kPa to 150 kPa?
Liono4ka [1.6K]

Answer:

new Volume of gas=360L

Explanation:

Assume that given gas follow the ideality nature of gas

Assuming that temperature is constant;

P1 and V1 are the initial parameter of gas

and p2 and V2 are the parameter after increasing the pressure

according to boyle 's law pressure is inversly proportional to the volume at constant temperature.

P_1V_1=P_2V_2

given value of volume and gas

P1=90kPa

V1=600L

P2=150kPa

V2=?

After putting all values we get;

V2=360L

new Volume of gas=360L

7 0
3 years ago
The temperature of a 95.4 g piece of Cu increases from 25.0 °C to 48.0 °C when the Cu absorbs 849 J of heat. What is the specifc
melisa1 [442]
<h3>Answer:</h3>

0.387 J/g°C

<h3>Explanation:</h3>
  • To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
  • Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
  • That is, Q = mcΔT

in our question we are given;

Mass of copper, m as 95.4 g

Initial temperature = 25 °C

Final temperature = 48 °C

Thus, change in temperature, ΔT = 23°C

Quantity of heat absorbed, Q as 849 J

We are required to calculate the specific heat capacity of copper

Rearranging the formula we get

c = Q ÷ mΔT

Therefore,

Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)

                                        = 0.3869 J/g°C

                                        = 0.387 J/g°C

Therefore, the specific heat capacity of copper is 0.387 J/g°C

3 0
3 years ago
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