383 mL of 3.50 M muriatic acid solution
Explanation:
First we calculate the number of moles of HCl:
number of moles = mass / molecular weight
number of moles of HCl = 47.7 / 35.5 = 1.34 moles
Now to determine the volume of the 3.50 M muriatic acid (clorhidric acid) solution, we use the following formula:
molar concentration = number of moles / volume (L)
volume (L) = number of moles / molar concentration
volume of the muriatic acid solution = 1.34 / 3.5 = 0.383 L = 383 mL
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Acetylene on combustion produces CO₂ and H₂O,
C₂H₂ + 7/2 O₂ → 2 CO₂ + 3 H₂O
According to Balance equation,
28.05 g of C₂H₂ produces = 2 moles of CO₂
So,
5.80 g of C₂H₂ will produce = X moles of CO₂
Solving for X,
X = (5.80 g × 2 mol) ÷ 28.05 g
X = 0.41 Moles of CO₂
The amount of solute in the solution will remain at the bottom of the vessel which it was pit
All i know that we are HOOman
We know that, M1V1 = M2V2
(Initial) (Final)
where, M1 and M2 are initial and final concentration of soution respectively.
V1 and V2 = initial and final volume of solution respectively
Given: M1 = 12 m, V1 = 35 ml and V2 = 1.2 l = 1200 ml
∴ M2 = M1V1/V2 = (12 × 35)/ 1200 = 0.35 m
Final concentration of solution is 0.35 m