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meriva
3 years ago
8

What is the pH of 15 mL of .2 M HCl

Chemistry
1 answer:
fenix001 [56]3 years ago
3 0
Easy peasy! All we need to do is plug this formula into our calculator:

-log(M)

So, we'd plug in -log(.2), which is 0.7 :)
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cricket20 [7]
D is the answer I believe.
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Given a 0.200 M solution of anserine at its isoelectric point and ready access to 0.100 M HCl, 0.100 M NaOH and distilled water,
vekshin1

Solution :

Given :

Amount of anserine solution = 0.200 M

pH value is = 7.20

Preparation of 0.04 M solution of anserine from the 0.2 M solution.

0.2 M x x = 0.04 M x 1000 ml

x = 200 ml

So the 200 ml of 0.2 M anserine solution is required to prepare0.04 M of anserine.

0.1 M x x = 0.04 x 1000 ml

x = 400 ml

Therefore, 400 ml of HCl is needed.

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Coal is a natural resource.
Afina-wow [57]

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2 years ago
Molar mass of osmium
lidiya [134]

Answer:-

190.23 gram mol-1

Explanation:-

Molar mass is the mass of 1 mole of that substance. It's unit is gram / mol or gram mol-1.

For an element it is equal to it's atomic weight.

The atomic weight of Osmium is 190.23

Hence the molar mass of Osmium is 190.23 gram / mol

7 0
3 years ago
How do you balance the following solution Zn(s)+HCI(aq)—>ZnCI2 (aq) + H2(g)
Ierofanga [76]

<u>Answer:</u> The atoms of every element on both the sides of the reaction must be same.

<u>Explanation:</u>

We are given a chemical equation and we need to balance it. Every equation follows Law of Conservation of mass.

This law states that in a chemical reaction, the number of atoms of each element must be same on both the sides of the equation.

For the given chemical equation:

Zn(s)+HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

On reactant side:

Number of zinc atoms = 1

Number of hydrogen atoms = 1

Number of chlorine atoms = 1

On product side:

Number of zinc atoms = 1

Number of hydrogen atoms = 2

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As, the number of hydrogen and chlorine atoms on reactant and product side is not same, so we need to add a stoichiometric coefficient in-front of HCl on the reactant side. The balanced chemical equation becomes:

Zn(s)+2HCl(aq)\rightarrow ZnCl_2(aq)+H_2(g)

8 0
3 years ago
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