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damaskus [11]
3 years ago
15

PEASE RESPOND QUICKLY WILL GIVE BRAINLIST!!!!!!!!

Chemistry
2 answers:
Amiraneli [1.4K]3 years ago
8 0

Answer:

C

Explanation:

SO42− is the polyatomic ion that will form an ionic compound with a single sodium ion

romanna [79]3 years ago
5 0

Answer:

D).

{ \tt{NO_{3} {}^{ - } }}

Explanation:

The nitrate ion because it is a radical with a valence of 1, forming sodium nitrate.

{ \tt{Na {}^{ + } .NO _{3}  {}^{ - } }}

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To create an isotopeof a certain element, you must vary a number of:
lesya692 [45]
Probably protons because when it changes it becomes a whole new element
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3 years ago
What most likely occurred during this demonstration?
Katena32 [7]

Answer:

Hydrogen gas and a salt formed at the end of the reaction.

Explanation:

Hydrogen Gas has formed which inflated the balloon

Usually, metals and acids react to form a salt and Hydrogen Gas.

Here's what happened:

Zn (s) + 2HCl (aq) →  ZnCl_2(aq) +H_2(g)

Cheers :)

7 0
3 years ago
What is the mass of 2.15 liters of N2 gas at STP?
ivann1987 [24]

Explanation:

mole number =mass/molar mass

mass=mole number × molar mass

mass= (volume of gas/volume at stp)molar mass

mass=(2.15/22.4)28

mass=2.69g

pls give brainliest

6 0
3 years ago
In preparation for a blizzard, a city dispatches a crew to spread salt on the street surface of the bridges around town . The sa
4vir4ik [10]
I believe it is A because 32C would be way too much and it wouldnt go down to -5
6 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: P4(g) + 10 Cl2(g) → 4PCl5(s) ΔH
Pie

Answer: -1835 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

PCl_5(s)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H_1=+157kJ (1)

P_4(g)+6Cl_2\rightarrow 4PCl_3(g)  \Delta H_2=-1207J (2)

Net chemical equation:

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H=? (3)

Multiplying equation (1) by 4,  and reversing we get

4PCl_3(g)+4Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_4=4\times -157kJ=-628kJ (4)

Adding (2) and (4)

P_4(g)+10Cl_2(g)\rightarrow 4PCl_5(s)  \Delta H_3=\Delta H_2+\Delta H_4=-1207kJ-628kJ=-1835kJ  

Thus enthaply change for the reaction is -1835 kJ.

3 0
4 years ago
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