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1 year ago

The radius of a circle is 4 m. Find its area to the nearest whole number.

Mathematics

2 answers:

Slav-nsk [51]1 year ago

6 0

Answer:

16π or around 50.26

Step-by-step explanation:

A=πr²

A=π(4)²

A=16π

A=16(3.1415926)

A=50.26

dusya [7]1 year ago

3 0

I think it’s A≈50.27m²

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sandy is cutting bows out of ribbon which will be used to rap gifts. If sandy need 9/7 feet of ribbon to make a bow and she has

Katarina [22]

Sandy can make 14 bows

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2 years ago

Alaina needs to sell 225 boxes in order to be the top seller. She sells thin mints and samoas to all of her customers for a tota

Digiron [165]

Answer:

94 boxes of samoas

131 boxes of thin mints

Step-by-step explanation:

m=mints

s=samoas

s+m=225 m=225-s

s(2.5)+m(3)=628

2.5s+3m=628

substitute for m

2.5s+3(225-s)=628

2.5s+675-3s=628

reduce

-0.5s=-47

s=94

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4 0

2 years ago

What is the interquartile range of the data set? Enter the answer in the box. Key: 1|5 means 15

Aneli [31]

First of all we have to arrange the data in ascending order as shown below:

28, 40, 43, 43, 45, 50, 50

Total number of values = 7

Since the number of values is odd, the median will be the middle value i.e. 4th value which is 43. Median divides the data in two halves:

1st Half = 28, 40, 43
2nd Half = 45, 50, 50

Q1 or the First Quartile is the middle value of the lower or 1st half which is 40.
Q3 or the Third Quartile is the middle value of the upper or second half, which is 50.

IQR or the Inter Quartile Range is the difference of Q3 and Q1.

So, IQR= Q3 – Q1 = 50 – 40 = 10

Thus, IQR for the given data is 10

4 0

2 years ago

Read 2 more answers

Hello can someone help me simplify 4) and 5)? Thank you and please include steps :)

Leni [432]

Alrighty

remember some rules
$(ab)^c=(a^c)(b^c)$
and
$x^{-m}=\frac{1}{x^m}$
and
$x^0=1$ for all real values of x
and
$(a^b)^c=a^{bc}$
and
$(\frac{a}{b})^c=\frac{a^c}{b^c}$
and
(a/b)/(c/d)=(ad)/(bc)
and
$(a^b)(a^c)=a^{b+c}$
and
$\frac{a^m}{a^n}=a^{m-n}$
and don't forget pemdas
example: $-x^m=-1(x^m)$ but $(-x)^m=(-1)^m(x^m)$

so

4.
$(\frac{c^{-2}}{2})^{-2}=$

$\frac{(c^{-2})^{-2}}{2^{-2}}=$

$\frac{c^4}{\frac{1}{2^2}}=$

$\frac{c^4}{\frac{1}{4}}=$

$4c^4$

5.

$\frac{(-a)^4bc^5}{-a^2b^{-3}c^0}=$

$\frac{(-1)^4(a)^4bc^5}{-1(a^2)(\frac{1}{b^3}(1)}=$

$\frac{(1)a^4bc^5}{\frac{(-1)(a^2)}{b^3}}=$

$\frac{(a^4bc^5)b^3}{(-1)(a^2)}=$

$\frac{-a^4b^4c^5}{a^2}=$

$-a^2b^4c^5$

3 0

2 years ago

311 students went on a field trip. Six buses were

kow [346]

Answer:

50.6

Step-by-step explanation:

it says 7 students traveled by car so you need to take 7 from 311, then divide your answer (304) by 6, which is 50.6

5 0

2 years ago

Read 2 more answers